A299754 Number of distinct sums of n complex n-th roots of 1.
1, 3, 10, 25, 126, 127, 1716, 2241, 18469, 15231, 352716, 36973, 5200300, 1799995, 30333601, 24331777, 1166803110, 12247363, 17672631900, 723276561
Offset: 1
Keywords
Examples
From _M. F. Hasler_, Feb 18 2018: (Start) For n=2, the n-th roots of unity are U[2] = {-1, 1}, and taking x, y in this set, we can get x + y = -2, 0 or 2. For n=3, the n-th roots of unity are U[3] = {1, w, w^2} where w = exp(2i*Pi/3) = -1/2 + i sqrt(3)/2, and taking x, y, z in this set, we can get x + y + z to be any of the 10 distinct values { 3, 2 + w, 2 + w^2, 1 + 2w, 1 + 2w^2, 0, w - 1, w^2 - 1, 3w, 3w^2 }. (End)
Programs
-
Maple
nexti:= proc(i,N) local ip,j,k; ip:= i; for k from N to 1 by -1 while i[k]=N-1 do od; if k=0 then return NULL fi; ip[k]:= ip[k]+1; for j from k+1 to N do ip[j]:= ip[k] od; ip end proc: f:= proc(N) local S, i,P,z; S:= {}: i:= <(0$N)>: P:= numtheory:-cyclotomic(N,z); while i <> NULL do S:= S union {rem(add(z^i[k],k=1..N),P,z)}; i:= nexti(i,N); od; nops(S); end proc: seq(f(N),N=1..10); # Robert Israel, Feb 18 2018
-
Mathematica
a[n_] := (t = Table[Exp[2 k Pi I/n], {k, 0, n - 1}]; b[0] = 1; iter = Table[{b[j], b[j - 1], n}, {j, 1, n}]; msets = Table[Array[b, n], Evaluate[Sequence @@ iter]]; tot = Total /@ (t[[#]] & /@ Flatten[msets, n - 1]) // N; u = Union[tot, SameTest -> (Chop[Abs[#1 - #2]] == 0 &)]; u // Length); Table[an = a[n]; Print["a(", n, ") = ", an]; an, {n, 1, 10}] (* Jean-François Alcover, Feb 19 2018 *)
-
PARI
a(n,U=vector(n,k,bestappr(exp(2*Pi/n*k*I),5*2^n)),S=[])={forvec(i=vector(n,k,[1,n]),S=setunion(S,[vecsum(vecextract(U,i))]));#S} \\ Not very efficient for n > 8. - M. F. Hasler, Feb 18 2018
Formula
For prime p, a(p) = binomial(2*p-1,p). - Conjectured by Robert Israel, Feb 18 2018; proved by Max Alekseyev, Feb 20 2018
a(n) = A299807(n,n). - Max Alekseyev, Feb 25 2018
Extensions
a(1) through a(11) from Robert Israel, Feb 18 2018
a(12)-a(13) from Chai Wah Wu, Feb 20 2018
a(14)-a(20) from Max Alekseyev, Feb 22 2018
Comments