cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A308085 a(n) is the least positive number k such that n*(n-1)/2 + k*(k-1)/2 is a square.

Original entry on oeis.org

1, 1, 2, 3, 4, 2, 6, 7, 1, 9, 10, 6, 3, 13, 14, 2, 16, 17, 18, 4, 6, 21, 3, 23, 24, 9, 5, 27, 13, 4, 30, 31, 2, 6, 34, 35, 5, 37, 38, 16, 7, 30, 23, 6, 44, 20, 46, 8, 16, 1, 7, 51, 12, 53, 9, 42, 23, 8, 58, 59, 60, 10, 27, 63, 9, 65, 20, 67, 11, 69, 6, 10, 72, 3, 44, 12, 21, 77, 11, 34, 80, 46
Offset: 1

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Author

J. M. Bergot and Robert Israel, Jun 05 2019

Keywords

Comments

a(n) <= n-1 if n > 1, because (n-1)*(n-2)/2 + n*(n-1)/2 = (n-1)^2.
a(7*k+2) <= k and a(7*k+6) <= k+2, because (7*k+2)*(7*k+1)/2 + k*(k-1)/2 = (5*k+1)^2 and (7*k+6)*(7*k+5)/2 + (k+2)*(k+1)/2 = (5*k+4)^2.
From Bernard Schott, Jun 27 2019: (Start)
a(m) = 1 iff the triangular number t(m-1) = (m-1)*m/2 is a square, so iff m-1 is in A001108, or m in A055997.
a(m) = 2 iff the triangular number t(m-1) + 1 is a square, so iff m-1 is in A006451. (End)

Examples

			a(5) = 4 because 4*3/2 + 5*4/2 = 4^2 and none of 1*0/2 + 5*4/2, 2*1/2 + 5*4/2, 3*2/2 + 5*4/2 are squares.
		

Crossrefs

Cf. A000217, A055997 (a(n)=1).

Programs

  • Maple
    f:= proc(n) local k;
      for k from 1 do
        if issqr((k*(k-1)+n*(n-1))/2) then return k fi
      od
    end proc:
    map(f, [$1..100]);
  • PARI
    a(n) = {my(k=1); while (!issquare(n*(n-1)/2 + k*(k-1)/2), k++); k;} \\ Michel Marcus, Jun 27 2019