A309465 Sum of the prime parts in the partitions of n into 4 parts.
0, 0, 0, 0, 0, 2, 7, 11, 28, 31, 56, 68, 101, 117, 165, 187, 267, 307, 385, 445, 563, 621, 780, 878, 1044, 1181, 1405, 1545, 1828, 2019, 2298, 2535, 2901, 3141, 3588, 3915, 4371, 4768, 5311, 5711, 6393, 6880, 7552, 8146, 8957, 9543, 10493, 11218, 12194
Offset: 0
Keywords
Examples
Figure 1: The partitions of n into 4 parts for n = 8, 9, ..
1+1+1+9
1+1+2+8
1+1+3+7
1+1+4+6
1+1+1+8 1+1+5+5
1+1+2+7 1+2+2+7
1+1+1+7 1+1+3+6 1+2+3+6
1+1+2+6 1+1+4+5 1+2+4+5
1+1+3+5 1+2+2+6 1+3+3+5
1+1+1+6 1+1+4+4 1+2+3+5 1+3+4+4
1+1+1+5 1+1+2+5 1+2+2+5 1+2+4+4 2+2+2+6
1+1+2+4 1+1+3+4 1+2+3+4 1+3+3+4 2+2+3+5
1+1+3+3 1+2+2+4 1+3+3+3 2+2+2+5 2+2+4+4
1+2+2+3 1+2+3+3 2+2+2+4 2+2+3+4 2+3+3+4
2+2+2+2 2+2+2+3 2+2+3+3 2+3+3+3 3+3+3+3
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n | 8 9 10 11 12 ...
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a(n) | 28 31 56 68 101 ...
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- _Wesley Ivan Hurt_, Sep 08 2019
Links
Programs
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Mathematica
Table[Sum[Sum[Sum[i (PrimePi[i] - PrimePi[i - 1]) + j (PrimePi[j] - PrimePi[j - 1]) + k (PrimePi[k] - PrimePi[k - 1]) + (n - i - j - k) (PrimePi[n - i - j - k] - PrimePi[n - i - j - k - 1]), {i, j, Floor[(n - j - k)/2]}], {j, k, Floor[(n - k)/3]}], {k, Floor[n/4]}], {n, 0, 80}]
Formula
a(n) = Sum_{k=1..floor(n/4)} Sum_{j=k..floor((n-k)/3)} Sum_{i=j..floor((n-j-k)/2)} (i * c(i) + j * c(j) + k * c(k) + (n-i-j-k) * c(n-i-j-k)), where c is the prime characteristic (A010051).