cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A318651 a(n) = A046644(n)/A318512(n).

Original entry on oeis.org

1, 2, 1, 8, 1, 4, 1, 16, 1, 4, 1, 16, 1, 4, 1, 128, 1, 4, 1, 16, 1, 4, 1, 32, 1, 4, 1, 16, 1, 4, 1, 256, 1, 4, 1, 16, 1, 4, 1, 32, 1, 4, 1, 16, 1, 4, 1, 256, 1, 4, 1, 16, 1, 4, 1, 32, 1, 4, 1, 16, 1, 4, 1, 1024, 1, 4, 1, 16, 1, 4, 1, 64, 1, 4, 1, 16, 1, 4, 1, 256, 1, 4, 1, 16, 1, 4, 1, 32, 1, 4, 1, 16, 1, 4, 1, 512, 1, 4, 1, 16, 1, 4, 1, 32, 1
Offset: 1

Views

Author

Antti Karttunen, Aug 31 2018

Keywords

Crossrefs

Programs

Formula

a(n) = A046644(n)/A318512(n).
a(n) = 2^A318652(n).

A318654 Positions of even terms in A318649.

Original entry on oeis.org

2, 4, 8, 16, 24, 32, 40, 56, 64, 88, 96, 104, 128, 136, 152, 160, 184, 192, 224, 232, 248, 256, 296, 320, 328, 344, 352, 376, 384, 416, 424, 448, 472, 488, 512, 536, 544, 568, 584, 608, 632, 640, 664, 704, 712, 736, 776, 808, 824, 832, 856, 872, 896, 904, 928, 992, 1016, 1024, 1048, 1088, 1096, 1112, 1184, 1192, 1208, 1216, 1256, 1304
Offset: 1

Views

Author

Antti Karttunen, Sep 01 2018

Keywords

Comments

Positions of nonzero terms in A318655.
It appears that these are also the positions of even terms in A318511.

Crossrefs

A318655 The 2-adic valuation of A318649, the numerators of "Dirichlet Square Root" of squares.

Original entry on oeis.org

0, 1, 0, 1, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0
Offset: 1

Views

Author

Antti Karttunen, Sep 01 2018

Keywords

Comments

Probably also the 2-adic valuation of A318511.

Crossrefs

Cf. A318511, A318649, A318651, A318652, A318654 (the positions of nonzero terms).

Programs

Formula

a(n) = A007814(A318649(n)).
It seems that for all n >= 1, a(n) <= A007814(A064549(n)) <= A007814(A000290(n)).
Showing 1-3 of 3 results.