cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A319630 Positive numbers that are not divisible by two consecutive prime numbers.

Original entry on oeis.org

1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 16, 17, 19, 20, 21, 22, 23, 25, 26, 27, 28, 29, 31, 32, 33, 34, 37, 38, 39, 40, 41, 43, 44, 46, 47, 49, 50, 51, 52, 53, 55, 56, 57, 58, 59, 61, 62, 63, 64, 65, 67, 68, 69, 71, 73, 74, 76, 79, 80, 81, 82, 83, 85, 86, 87
Offset: 1

Views

Author

Rémy Sigrist, Sep 25 2018

Keywords

Comments

This sequence is the complement of A104210.
Equivalently, this sequence corresponds to the positive numbers k such that:
- A300820(k) <= 1,
- A087207(k) is a Fibbinary number (A003714).
For any n > 0 and k >= 0, a(n)^k belongs to the sequence.
The numbers of terms not exceeding 10^k, for k=1,2,..., are 9, 78, 758, 7544, 75368, 753586, 7535728, 75356719, 753566574, ... Apparently, the asymptotic density of this sequence is 0.75356... - Amiram Eldar, Apr 10 2021
Numbers not divisible by any term of A006094. - Antti Karttunen, Jul 29 2022

Examples

			The number 10 is only divisible by 2 and 5, hence 10 appears in the sequence.
The number 42 is divisible by 2 and 3, hence 42 does not appear in the sequence.
		

Crossrefs

Cf. A003714, A006094, A087207, A104210, A300820, A356171 (odd terms only).
Positions of 1's in A322361 and in A356173 (characteristic function).

Programs

  • Maple
    N:= 1000: # for terms <= N
    R:= {}:
    p:= 2:
    do
      q:= p; p:= nextprime(p);
      if p*q > N then break fi;
      R:= R union {seq(i,i=p*q..N,p*q)}
    od:
    sort(convert({$1..N} minus R,list)); # Robert Israel, Apr 13 2020
  • Mathematica
    q[n_] := SequenceCount[FactorInteger[n][[;; , 1]], {p1_, p2_} /; p2 == NextPrime[p1]] ==  0; Select[Range[100], q] (* Amiram Eldar, Apr 10 2021 *)
  • PARI
    is(n) = my (f=factor(n)); for (i=1, #f~-1, if (nextprime(f[i,1]+1)==f[i+1,1], return (0))); return (1)

Formula

A300820(a(n)) <= 1.