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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A319847 Irregular triangle read by rows in which row n lists the odd divisors of n in increasing order together with the even divisors of n in increasing order.

Original entry on oeis.org

1, 1, 2, 1, 3, 1, 2, 4, 1, 5, 1, 3, 2, 6, 1, 7, 1, 2, 4, 8, 1, 3, 9, 1, 5, 2, 10, 1, 11, 1, 3, 2, 4, 6, 12, 1, 13, 1, 7, 2, 14, 1, 3, 5, 15, 1, 2, 4, 8, 16, 1, 17, 1, 3, 9, 2, 6, 18, 1, 19, 1, 5, 2, 4, 10, 20, 1, 3, 7, 21, 1, 11, 2, 22, 1, 23, 1, 3, 2, 4, 6, 8, 12, 24, 1, 5, 25, 1, 13, 2, 26, 1, 3, 9, 27
Offset: 1

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Author

Omar E. Pol, Sep 29 2018

Keywords

Comments

Consider the diagram with overlapping periodic curves that appears in the Links section (figure 1). The number of curves that contain the point [n,0] equals the number of divisors of n. The simpler interpretation of the diagram is that the curve of diameter d represents the divisor d of n. Now here we introduce a new interpretation: the curve of diameter d that contains the point [n,0] represents the divisor c of n, where c = n/d. This model has the property that each odd quadrant centered at [n,0] contains the curves that represent the even divisors of n, and each even quadrant centered at [n,0] contains the curves that represent the odd divisors of n.
We can find the n-th row of the triangle as follows:
Consider only the semicircumferences that contain the point [n,0].
In the second quadrant from top to bottom we can see the curves that represent the odd divisors of n in increasing order. Also we can see these curves in the fourth quadrant from bottom to top.
Then, if n is an even number, in the first quadrant from top to bottom we can see the curves that represent the even divisors of n in increasing order. Also we can see these curves in the third quadrant from bottom to top (see example).
Sequences of the same family are shown below:
-----------------------------------
Triangle Order of divisors of n
-----------------------------------
A299481 odd v t.w. even ^
A299483 odd ^ t.w. even v
A319844 even v t.w. odd ^
A319845 even ^ t.w. odd v
A319846 odd v t.w. even v
This seq. odd ^ t.w. even ^
A319848 even v t.w. odd v
A319849 even ^ t.w. odd ^
-----------------------------------
In the above table we have that:
"even v" means "even divisors of n in decreasing order".
"even ^" means "even divisors of n in increasing order".
"odd v" means "odd divisors of n in decreasing order".
"odd ^" means "odd divisors of n in increasing order".
"t.w." means "together with".

Examples

			Triangle begins:
1;
1,  2;
1,  3;
1,  2,  4;
1,  5;
1,  3,  2,  6;
1,  7;
1,  2,  4,  8;
1,  3,  9;
1,  5,  2, 10;
1, 11;
1,  3,  2,  4,  6, 12;
1, 13;
1,  7,  2, 14;
1,  3,  5, 15;
1,  2,  4,  8, 16;
1, 17;
1,  3,  9,  2,  6, 18;
1, 19;
1,  5,  2,  4, 10, 20;
1,  3,  7, 21;
1, 11,  2, 22;
1, 23;
1,  3,  2,  4,  6,  8, 12, 24;
1,  5, 25;
1, 13,  2, 26;
1,  3,  9, 27;
1,  7,  2,  4, 14, 28;
...
For n = 12 the divisors of 12 are [1, 2, 3, 4, 6, 12]. The odd divisors of 12 in increasing order are [1, 3], and the even divisors of 12 in increasing order are [2, 4, 6, 12], so the 12th row of triangle is [1, 3, 2, 4, 6, 12].
On the other hand, consider the diagram that appears in the Links section (figure 1). Then consider only the semicircumferences that contain the point [12,0]. In the second quadrant, from top to bottom, we can see the curves with diameters [12, 4]. Also we can see these curves in the fourth quadrant from bottom to top. The associated numbers c = 12/d are [1, 3] respectively. These are the odd divisors of 12 in increasing order. Then, in the first quadrant, from top to bottom, we can see the curves with diameters [6, 3, 2, 1]. Also we can see these curves in the third quadrant from bottom to top. The associated numbers c = 12/d are [2, 4, 6, 12] respectively. These are the even divisors of n in increasing order. Finally all numbers c obtained are [1, 3, 2, 4, 6, 12] equaling the 12th row of triangle.
		

Crossrefs

A permutation of A027750 from which first differs at a(12) = T(6,2).
Row sums give A000203.
Row n has length A000005(n).
Column 1 gives A000012.
Right border gives A000027.

Programs

  • PARI
    row(n) = my(d=divisors(n)); concat(select(x->(x%2), d), select(x->!(x%2), d));
    lista(nn) = {for (n=1, nn, my(r = row(n)); for (k=1, #r, print1(r[k], ", ")););} \\ Michel Marcus, Jan 17 2019