A321440 Number of partitions of n into consecutive parts, all singletons except the largest.
1, 1, 2, 3, 3, 4, 5, 4, 5, 7, 5, 6, 8, 5, 8, 10, 5, 8, 10, 7, 10, 11, 7, 8, 13, 9, 9, 14, 7, 12, 15, 6, 12, 13, 11, 15, 14, 8, 10, 19, 10, 12, 18, 8, 16, 19, 9, 12, 17, 14, 16, 16, 10, 15, 21, 15, 14, 20, 7, 16, 25, 7, 20, 21, 14, 18, 18, 14, 12, 26, 16, 17
Offset: 0
Keywords
Examples
Here are the derivations of the terms given. Partitions are listed as strings of digits. n = 0: (empty partition) n = 1: 1 n = 2: 11, 2 n = 3: 111, 12, 3 n = 4: 1111, 22, 4 n = 5: 11111, 122, 23, 5 n = 6: 111111, 123, 222, 33, 6 n = 7: 1111111, 1222, 34, 7 n = 8: 11111111, 2222, 233, 44, 8 n = 9: 111111111, 12222, 1233, 234, 333, 45, 9 n = 10: 1111111111, 1234, 22222, 55, (10)
Links
- Chai Wah Wu, Table of n, a(n) for n = 0..10000
- C. Alfes, K. Bringmann, and J. Lovejoy, Automorphic properties of generating functions for generalized odd rank moments and odd Durfee symbols, Math. Proc. Cambridge Philos. Soc. 151 (2011), no. 3, 385-406.
- Dandan Chen and Rong Chen, Generating Functions of the Hurwitz Class Numbers Associated with Certain Mock Theta Functions, arXiv:2107.04809 [math.NT], 2021.
- N. J. A. Sloane, Coordination Sequences, Planing Numbers, and Other Recent Sequences (II), Experimental Mathematics Seminar, Rutgers University, Jan 31 2019, Part I, Part 2, Slides. (Mentions this sequence)
Crossrefs
See comment by Emeric Deutsch at A001227 (partitions into consecutive parts, all singletons); the partitions considered in the present sequence are a superset of those described by Deutsch.
Programs
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Python
from sympy.utilities.iterables import partitions def A321440(n): return 1 if n == 0 else sum(1 for s,p in partitions(n,size=True) if len(p)-1 == max(p)-min(p) == s-p[max(p)]) # Chai Wah Wu, Nov 09 2018
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Python
from _future_ import division def A321440(n): # a faster program based on the characterization in the comments if n == 0: return 1 c = 0 for i in range(n): mi = i*(i+1)//2 + n for j in range(i+1,n+1): k = mi - j*(j+1)//2 if k < 0: break if not k % j: c += 1 return c # Chai Wah Wu, Nov 09 2018
Formula
From Jeremy Lovejoy, Nov 10 2022: (Start)
G.f.: 1 + Sum_{n>=0} x^(n+1)*Product_{k=1..n} (1-x^(2*k))/Product_{k=1..n+1} (1-x^(2*k-1)).
G.f.: 1 + Sum_{n>=1} (-1)^(n+1)*x^(n^2)/((1-x^(2*n-1))*Product_{k=1..n} (1-x^(2*k-1))). (End)
Extensions
More terms from Chai Wah Wu, Nov 09 2018
Comments