A324923 Number of distinct factors in the factorization of n into factors q(i) = prime(i)/i, i > 0.
0, 1, 2, 1, 3, 2, 2, 1, 2, 3, 4, 2, 3, 2, 3, 1, 3, 2, 2, 3, 3, 4, 3, 2, 3, 3, 2, 2, 4, 3, 5, 1, 4, 3, 4, 2, 3, 2, 3, 3, 4, 3, 3, 4, 3, 3, 4, 2, 2, 3, 4, 3, 2, 2, 4, 2, 3, 4, 4, 3, 3, 5, 3, 1, 4, 4, 3, 3, 3, 4, 4, 2, 4, 3, 3, 2, 5, 3, 5, 3, 2, 4, 4, 3, 5, 3, 4, 4, 3, 3, 4, 3, 5, 4, 4, 2, 4, 2, 4, 3, 4, 4, 3, 3, 4, 2, 3, 2
Offset: 1
Keywords
Examples
The factorization 22 = q(1)^2 q(2) q(3) q(5) has four distinct factors, so a(22) = 4.
Links
Crossrefs
Programs
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Mathematica
difac[n_]:=If[n==1,{},With[{i=PrimePi[FactorInteger[n][[1,1]]]},Sort[Prepend[difac[n*i/Prime[i]],i]]]]; Table[Length[Union[difac[n]]],{n,100}]
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PARI
A006530(n) = if(1==n, n, my(f=factor(n)); f[#f~, 1]); A324923(n) = { my(lista = List([]), gpf, i); while(n > 1, gpf=A006530(n); i = primepi(gpf); n /= gpf; n *= i; listput(lista,i)); #Set(lista); }; \\ Antti Karttunen, Oct 23 2023
Formula
a(n) = A317713(n) - 1.
Extensions
Data section extended up to a(108) by Antti Karttunen, Oct 23 2023
Comments