A325641 a(1) = 1; for n > 1, a(n) = n/d for the least divisor d > 1 of n such that A048720(d,k) = n for some k.
1, 1, 1, 2, 1, 3, 1, 4, 3, 5, 1, 6, 1, 7, 5, 8, 1, 9, 1, 10, 3, 11, 1, 12, 1, 13, 9, 14, 1, 15, 1, 16, 11, 17, 5, 18, 1, 19, 13, 20, 1, 21, 1, 22, 15, 23, 1, 24, 7, 25, 17, 26, 1, 27, 1, 28, 19, 29, 1, 30, 1, 31, 21, 32, 13, 33, 1, 34, 1, 35, 1, 36, 1, 37, 25, 38, 1, 39, 1, 40, 1, 41, 1, 42, 17, 43, 1, 44, 1, 45, 1, 46, 3, 47, 19
Offset: 1
Keywords
Links
Programs
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PARI
A325641(n) = if(1==n,n, my(p = Pol(binary(n))*Mod(1, 2)); fordiv(n,d,if((d>1),my(q = Pol(binary(d))*Mod(1, 2)); if(0==(p%q), return(n/d)))));
Formula
a(n) = n / A325643(n).