A325686 Number of strict length-3 compositions x + y + z = n satisfying x + y != z and x != y + z.
0, 0, 0, 0, 0, 0, 2, 6, 8, 18, 16, 30, 34, 48, 48, 72, 72, 96, 98, 126, 128, 162, 160, 198, 202, 240, 240, 288, 288, 336, 338, 390, 392, 450, 448, 510, 514, 576, 576, 648, 648, 720, 722, 798, 800, 882, 880, 966, 970, 1056, 1056, 1152, 1152, 1248, 1250, 1350, 1352
Offset: 0
Keywords
Examples
The a(6) = 2 through a(10) = 16 compositions: (132) (124) (125) (126) (127) (231) (142) (143) (135) (136) (214) (152) (153) (154) (241) (215) (162) (163) (412) (251) (216) (172) (421) (341) (234) (217) (512) (243) (253) (521) (261) (271) (315) (316) (324) (352) (342) (361) (351) (451) (423) (613) (432) (631) (513) (712) (531) (721) (612) (621)
Links
- Fausto A. C. Cariboni, Table of n, a(n) for n = 0..5000
Crossrefs
Programs
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Mathematica
Table[Length[Cases[Join@@Permutations/@IntegerPartitions[n,{3}],{x_,y_,z_}/;x!=y!=z&&x+y!=z &&x!=y+z]],{n,0,30}]
Formula
Conjectures from Colin Barker, May 14 2019: (Start)
G.f.: 2*x^6*(1 + 3*x + 3*x^2 + 5*x^3) / ((1 - x)^3*(1 + x)^2*(1 + x^2)*(1 + x + x^2)).
a(n) = a(n-2) + a(n-3) + a(n-4) - a(n-5) - a(n-6) - a(n-7) + a(n-9) for n>9. (End)
Above conjecture confirmed for n <= 5000. - Fausto A. C. Cariboni, Feb 17 2022
Comments