cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A332151 a(n) = 5*(10^(2*n+1)-1)/9 - 4*10^n.

Original entry on oeis.org

1, 515, 55155, 5551555, 555515555, 55555155555, 5555551555555, 555555515555555, 55555555155555555, 5555555551555555555, 555555555515555555555, 55555555555155555555555, 5555555555551555555555555, 555555555555515555555555555, 55555555555555155555555555555, 5555555555555551555555555555555
Offset: 0

Views

Author

M. F. Hasler, Feb 09 2020

Keywords

Crossrefs

Cf. A002275 (repunits R_n = (10^n-1)/9), A002279 (5*R_n), A011557 (10^n).
Cf. A138148 (cyclops numbers with binary digits), A002113 (palindromes).
Cf. A332121 .. A332191 (variants with different repeated digit 2, ..., 9).
Cf. A332150 .. A332159 (variants with different middle digit 0, ..., 9).

Programs

  • Maple
    A332151 := n -> 5*(10^(2*n+1)-1)/9-4*10^n;
  • Mathematica
    Array[5 (10^(2 # + 1)-1)/9 - 4*10^# &, 15, 0]
    Table[With[{c=PadRight[{},n,5]},FromDigits[Join[c,{1},c]]],{n,0,20}] (* Harvey P. Dale, Mar 16 2021 *)
  • PARI
    apply( {A332151(n)=10^(n*2+1)\9*5-4*10^n}, [0..15])
    
  • Python
    def A332151(n): return 10**(n*2+1)//9*5-4*10**n

Formula

a(n) = 5*A138148(n) + 10^n = A002279(2n+1) - 4*10^n.
G.f.: (1 + 404*x - 900*x^2)/((1 - x)(1 - 10*x)(1 - 100*x)).
a(n) = 111*a(n-1) - 1110*a(n-2) + 1000*a(n-3) for n > 2.