cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A332941 Lexicographically earliest sequence of positive numbers in which no set of consecutive terms sums to a prime.

Original entry on oeis.org

1, 8, 1, 15, 9, 1, 14, 6, 30, 6, 9, 15, 6, 4, 8, 12, 10, 14, 6, 12, 8, 10, 12, 18, 12, 6, 6, 6, 24, 6, 6, 8, 1, 9, 6, 10, 8, 12, 6, 14, 10, 6, 4, 8, 12, 10, 20, 6, 18, 6, 6, 4, 8, 12, 6, 4, 12, 8, 10, 8, 6, 6, 18, 6, 6, 20, 10, 12, 8, 4, 6, 12, 12, 6, 12, 6, 12
Offset: 1

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Author

S. Brunner, Mar 03 2020

Keywords

Comments

Terms >= 30 seem to be very rare. Up to a(450000), 30 appears only 7 times: at n = 9, 288, 2507, 15902, 54405, 242728, 425707.
For n <= 450000, the largest term is 32; it appears at n = 335308 and 370687.

Crossrefs

Programs

  • Maple
    s:= proc(i, j) option remember; `if`(i>j, 0, a(j)+s(i, j-1)) end:
    a:= proc(n) option remember; local k; for k while
          ormap(isprime, [k+s(i, n-1)$i=1..n]) do od; k
        end:
    seq(a(n), n=1..100);  # Alois P. Heinz, Mar 23 2020
  • Mathematica
    s[i_, j_] := s[i, j] = If[i > j, 0, a[j] + s[i, j-1]];
    a[n_] := a[n] = Module[{k}, For[k = 1, AnyTrue[k+Table[s[i, n-1], {i, 1, n}], PrimeQ], k++]; k];
    Array[a, 100] (* Jean-François Alcover, Nov 17 2020, after Alois P. Heinz *)
  • Python
    def A(ee):
        a=[1]
        print(1)
        n=1
        while n<=ee:
            i=1
            while i>0:
                ii=i
                iz=c=0
                while iz<=len(a):
                    c=0
                    if ii>2:
                        for j in range(2, int((ii)**0.5+1.5)):
                            if ii%j==0:
                                c=1
                                break
                    if c==0 and ii>1:
                        break
                    else:
                        iz += 1
                        ii=ii+a[n-iz]
                if c==1:
                    n += 1
                    a.append(i)
                    print(i)
                    break
                if i<4:
                    i=4
                else:
                    i += 1
        return a