cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A341541 a(n) is the number of steps to reach square 1 for a walk starting from square n along the shortest path on the square spiral board without stepping on any prime number. a(n) = -1 if such a path does not exist.

Original entry on oeis.org

0, 1, 2, 1, 2, 1, 2, 1, 2, 3, 4, -1, 4, 3, 2, 3, 4, 19, 2, 17, 16, 15, 2, 3, 4, 5, 4, 5, 6, 11, 6, 5, 4, 3, 4, 5, 6, 19, 18, 19, 18, 17, 16, 15, 14, 13, 4, 5, 6, 7, 6, 5, 6, 9, 10, 11, 10, 9, 6, 5, 4, 5, 6, 7, 8, 9, 10, 17, 18, 19, 18, -1, 16, 15, 14, 13, 12
Offset: 1

Views

Author

Ya-Ping Lu, Feb 14 2021

Keywords

Comments

Conjecture: There is no "island of two or more nonprimes" enclosed by primes on the square spiral board. If the conjecture is true, then numbers n such that a(n) = -1 are the terms in A341542.

Examples

			The shortest paths for a(n) <= 20 are illustrated in the figure attached in Links section. If more than one path are available, the path through the smallest number is chosen as the shortest path.
		

Crossrefs

Programs

  • Python
    from sympy import prime, isprime
    from math import sqrt, ceil
    def neib(m):
        if m == 1: L = [4, 6, 8, 2]
        else:
            n = int(ceil((sqrt(m) + 1.0)/2.0))
            z1 = 4*n*n - 12*n + 10; z2 = 4*n*n - 10*n + 7; z3 = 4*n*n - 8*n + 5
            z4 = 4*n*n - 6*n + 3; z5 = 4*n*n - 4*n + 1
            if m == z1:             L = [m + 1, m - 1, m + 8*n - 9, m + 8*n - 7]
            elif m > z1 and m < z2: L = [m + 1, m - 8*n + 15, m - 1, m + 8*n - 7]
            elif m == z2:           L = [m + 8*n - 5, m + 1, m - 1, m + 8*n - 7]
            elif m > z2 and m < z3: L = [m + 8*n - 5, m + 1, m - 8*n + 13, m - 1]
            elif m == z3:           L = [m + 8*n - 5, m + 8*n - 3, m + 1, m - 1]
            elif m > z3 and m < z4: L = [m - 1, m + 8*n - 3, m + 1, m - 8*n + 11]
            elif m == z4:           L = [m - 1, m + 8*n - 3, m + 8*n - 1, m + 1]
            elif m > z4 and m < z5: L = [m - 8*n + 9, m - 1, m + 8*n - 1, m + 1]
            elif m == z5:           L = [m - 8*n + 9, m - 1, m + 8*n - 1, m + 1]
        return L
    step_max = 20; L_last = [1]; L2 = L_last; L3 = [[1]]
    for step in range(1, step_max + 1):
        L1 = []
        for j in range(0, len(L_last)):
            m = L_last[j]; k = 0
            while k <= 3 and isprime(m) == 0:
                m_k = neib(m)[k]
                if m_k not in L1 and m_k not in L2: L1.append(m_k)
                k += 1
        L2 += L1; L3.append(L1); L_last = L1
    i = 1
    while i:
        if isprime(neib(i)[0])*isprime(neib(i)[1])*isprime(neib(i)[2])*isprime(neib(i)[3]) == 1: print(-1)
        elif i not in L2: break
        for j in range(0, len(L3)):
            if i in L3[j]: print(j); break
        i += 1

A336576 The final square number for a walk on a square spiral numbered board when starting on square 1 and stepping to an unvisited square containing the lowest prime number, where the square is within a block of size (2n+1) x (2n+1) centered on the current square. If no unvisited prime numbered squares exist within the block the walk ends.

Original entry on oeis.org

59, 947, 313, 3331, 5659, 67547, 253801, 676259, 3162413, 16604417, 29135971, 108235159, 437456497
Offset: 1

Views

Author

Scott R. Shannon, Jul 26 2020

Keywords

Comments

See A336494 for an explanation of the sequence and images of the walks.

Examples

			a(1) = 59. Starting from the square 1 the sequence of adjacent unvisited lowest primes the walk can step to are 2,3,11,29,13,31,59. Once the square 59 is visited there are no other unvisited adjacent squares containing primes, so the walk terminates.
		

Crossrefs

Cf. A336494 (total number of steps), A335856, A000040, A136626, A336092, A330979, A332767, A335661, A335364.
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