1, 1, 1, 1, 3, 1, 1, 2, 1, 3, 1, 5, 1, 1, 1, 1, 3, 1, 3, 1, 3, 1, 7, 1, 3, 1, 3, 1, 1, 4, 1, 5, 1, 5, 1, 5, 1, 9, 1, 3, 1, 3, 1, 7, 1, 1, 5, 1, 1, 1, 5, 1, 1, 1, 5, 1, 11, 1, 3, 1, 3, 1, 3, 1, 3, 1, 1, 6, 1, 9, 1, 9, 1, 9, 1, 9, 1, 9, 1, 13, 1, 1, 1, 5, 1, 1, 1, 5, 1, 1, 1, 1, 7, 1, 3, 1, 3
Offset: 1
Triangle T(n,k) begins:
n\k| 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
---+------------------------------------------------------
1 | 1;
2 | 1, 1;
3 | 1, 3, 1;
4 | 1, 2, 1, 3;
5 | 1, 5, 1, 1, 1;
6 | 1, 3, 1, 3, 1, 3;
7 | 1, 7, 1, 3, 1, 3, 1;
8 | 1, 4, 1, 5, 1, 5, 1, 5;
9 | 1, 9, 1, 3, 1, 3, 1, 7, 1;
10 | 1, 5, 1, 1, 1, 5, 1, 1, 1, 5;
11 | 1, 11, 1, 3, 1, 3, 1, 3, 1, 3, 1;
12 | 1, 6, 1, 9, 1, 9, 1, 9, 1, 9, 1, 9;
13 | 1, 13, 1, 1, 1, 5, 1, 1, 1, 5, 1, 1, 1;
14 | 1, 7, 1, 3, 1, 3, 1, 7, 1, 3, 1, 3, 1, 7;
15 | 1, 15, 1, 3, 1, 15, 1, 3, 1, 15, 1, 3, 1, 15, 1;
16 | 1, 8, 1, 5, 1, 9, 1, 5, 1, 9, 1, 5, 1, 9, 1, 5;
17 | 1, 17, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1;
...
For (n, k) = (7, 3), there are three nonnegative values of m < n such that m^3 == m (mod 7) (namely 0, 1, and 6) and one nonnegative value of m < n such that -m^3 == m (mod 7) (namely 0), so T(7,3) = 3/1 = 3.
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