A339713 a(n) = (a(n-2) concatenate a(n-1)) for n > 2, with a(1)=1, a(2)=10.

1, 10, 110, 10110, 11010110, 1011011010110, 110101101011011010110, 1011011010110110101101011011010110, 1101011010110110101101011011010110110101101011011010110, 10110110101101101011010110110101101101011010110110101101011011010110110101101011011010110

Offset: 1

Author

Wesley Ivan Hurt, Apr 24 2021

Keywords

• nonn
• base

Comments

Number of digits in a(n) = A000045(n+1). - Michael S. Branicky, Apr 24 2021

a(n) and a(n+1) contain Fibonacci(n) 1's and Fibonacci(n) 0's respectively.

Crossrefs

Cf. A000045, A111061 (in decimal), A061107, A131293.

Programs

Python

def aupton(terms):
  alst = [1, 10]
  for n in range(3, terms+1): alst.append(int(str(alst[-2])+str(alst[-1])))
  return alst[:terms]
print(aupton(10)) # Michael S. Branicky, Apr 24 2021