A341524 Number of prime factors in A017666(n), counted with multiplicity: a(n) = bigomega(n) - bigomega(gcd(n, sigma(n))).
0, 1, 1, 2, 1, 0, 1, 3, 2, 1, 1, 1, 1, 1, 1, 4, 1, 2, 1, 2, 2, 1, 1, 1, 2, 1, 3, 0, 1, 1, 1, 5, 1, 1, 2, 4, 1, 1, 2, 2, 1, 1, 1, 1, 2, 1, 1, 3, 2, 3, 1, 2, 1, 2, 2, 1, 2, 1, 1, 1, 1, 1, 3, 6, 2, 1, 1, 2, 1, 2, 1, 4, 1, 1, 3, 1, 2, 1, 1, 4, 4, 1, 1, 1, 2, 1, 1, 2, 1, 1, 1, 1, 2, 1, 1, 3, 1, 3, 2, 4, 1, 1, 1, 3, 2, 1, 1, 3, 1, 2, 2, 2, 1, 1, 2, 2, 2, 1, 2, 0
Offset: 1
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Mathematica
Table[PrimeOmega[n] - PrimeOmega[GCD[n, DivisorSigma[1, n]]], {n, 1, 100}] (* Amiram Eldar, Feb 17 2021 *)
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PARI
A341524(n) = (bigomega(n) - bigomega(gcd(n, sigma(n))));