A342019 Number of prime power divisors of the form p^p in the arithmetic derivative of A276086(n), the prime product form of primorial base expansion of n.
0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1
Offset: 1
Keywords
Examples
For n=108, A342002(108) = 36 = 2^2 * 3^2. Only the first prime power divisor is of the form p^p, thus a(108) = 1. Note that A276086(108) = A003415(42875) = 42875 = 5^3 * 7^3, and A327860(108) = 44100 = 2^2 * 3^2 * 5^2 * 7^2. The same "doom divisors" are always found both in A327860(n) and in A342002(n). For n=1164, A342002(1164) = 648 = 2^3 * 3^4. In both prime power divisors the exponent attains its base prime (3 >= 2 and 4 >= 3), thus a(1164) = 2. Note that A276086(1164) = 34525308125 = 5^4 * 7^3 * 11^5, and A327860(1164) = 58110129000 = 2^3 * 3^4 * 5^3 * 7^2 * 11^4. For n=18675300, A342002(18675300) = 3037500 = 2^2 * 3^5 * 5^5. Here all three prime power divisors are "doom divisors" because they reach the p^p limit, thus a(18675300) = 3.
Links
- Antti Karttunen, Table of n, a(n) for n = 1..65537
- Victor Ufnarovski and Bo Ã…hlander, How to Differentiate a Number, J. Integer Seqs., Vol. 6, 2003, #03.3.4.
- Index entries for sequences related to primorial base
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