cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A343232 Irregular triangle T read by rows: T(n, m) gives the solutions j of the congruence A002061(j+1) = j^2 + j + 1 == 0 (mod k(n)), with k(n) = A034017(n+1), for j from {0, 1, ..., k(n)-1}, and n >= 1.

Original entry on oeis.org

0, 1, 2, 4, 3, 9, 7, 11, 4, 16, 5, 25, 10, 26, 16, 22, 6, 36, 18, 30, 7, 49, 13, 47, 29, 37, 8, 64, 23, 55, 9, 16, 74, 81, 25, 67, 35, 61, 46, 56, 45, 63, 10, 100, 19, 107, 49, 79, 11, 30, 102, 121, 42, 96, 67, 79
Offset: 1

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Author

Wolfdieter Lang, Apr 08 2021

Keywords

Comments

The length of row n is A341422(n), the number of representative parallel primitive forms (rpapfs) for positive binary quadratic forms of Discriminant = -3 representing k = k(n) = A034017(n+1), for n >= 1.
These rpapfs for each j are [k(n), 2*j+1, (j^2 + j + 1)/k(n)], for n >= 1.
The solutions for k(n) >= 7 come in pairs j and k(n) - (1 + j). For k(1) = 1 and k(2) = 3 these pairs collapse to one solution.

Examples

			The irregular triangle T(n, m) begins:
n,   k(n)\m  1   2   3   4 ...   rpapfs
1,    1:     0                  [1,1,1]
2,    3:     1                  [3,3,1]
3,    7:     2   4              [7,5,1],      [7,9,3]
4,   13:     3   9              [13,7,1],     [13,19,7]
5,   19:     7  11              [19,15,3],    [19,23,7]
6,   21:    14  16              [21,9,1],     [21,33,13]
7,   31:     5  25              [31,11,1],    [31,51,21]
8,   37:    10  26              [37,21,3],    [37,53,19]
9,   39:    16  22              [39,33,7],    [39,45,13]
10,  43:     6  36              [43,13,1],    [43,73,31]
11,  49:    18  30              [49,37,7],    [49,61,19]
12,  57:     7  49              [57,15,1],    [57,99,43]
13,  61:    13  47              [61,27,3],    [61,95,37]
14,  67:    29  37              [67,59,13],   [67,75,21]
15,  73:     8  64              [73,17,1],    [73,129,57]
16,  79:    23  55              [79,47,7],    [79,111,39]
17,  91:     9  16              [91,19,1],    [91,33,3], [91,149,61],
                                [91,163,73]
18,  93:    25  67              [93,51,7],    [93,135,49]
19,  97:    35  61              [97,71,13] ,  [97,123,39]
20, 103:    46  56              [103,93,21],  [103,113,31]
21, 109:    45  63              [109,91,19],  [109,127,37]
22, 111:    10 100              [111,21,1],   [111,201,91]
23, 127:    19 107              [127,39,3],   [127,215,91]
24, 129:    49  79              [129,99,19],  [129,159,49]
25, 133:    11  30 102 121      [133, 23,1],  [133,61,7], [133,205,79],
                                [133,243,111]
26, 139     42  96              [139,85,13],  [139,193, 67]
27, 147:    67  79              [147,135,31], [147,159,43]
28, 151:    32 118              [151,65,7],   [151,237,93]
29, 157:    12 144              [157,25,1],   [157,289,133]
30, 163:    58 104              [163,117,21], [163,209,67]
...
		

Crossrefs

Formula

T(n, m) gives the solutions j of A002061(j+1) = j^2 + j + 1 == 0 (mod k(n)), for k(n) = A034017(n+1), for n >= 1.