A345373 Sum of the divisor complements of the unitary prime divisors of n.
0, 1, 1, 0, 1, 5, 1, 0, 0, 7, 1, 4, 1, 9, 8, 0, 1, 9, 1, 4, 10, 13, 1, 8, 0, 15, 0, 4, 1, 31, 1, 0, 14, 19, 12, 0, 1, 21, 16, 8, 1, 41, 1, 4, 9, 25, 1, 16, 0, 25, 20, 4, 1, 27, 16, 8, 22, 31, 1, 32, 1, 33, 9, 0, 18, 61, 1, 4, 26, 59, 1, 0, 1, 39, 25, 4, 18, 71, 1, 16, 0, 43
Offset: 1
Keywords
Examples
a(30) = 30 * Sum_{p|30, p prime} floor(1/gcd(p,30/p))/p = 30 * (1/2 + 1/3 + 1/5) = 31.
Crossrefs
Cf. A063956.
Formula
a(n) = n * Sum_{p|n, p prime} floor(1/gcd(p,n/p)) / p.
Comments