A347671 a(n) = n^n mod 100.

1, 1, 4, 27, 56, 25, 56, 43, 16, 89, 0, 11, 56, 53, 16, 75, 16, 77, 24, 79, 0, 21, 84, 67, 76, 25, 76, 3, 36, 69, 0, 31, 76, 13, 36, 75, 36, 17, 4, 59, 0, 41, 64, 7, 96, 25, 96, 63, 56, 49, 0, 51, 96, 73, 56, 75, 56, 57, 84, 39, 0, 61, 44, 47, 16, 25, 16, 23

Offset: 0

Author

John Bibby, Sep 10 2021

Keywords

• nonn
• base
• easy

Links

• Index entries for linear recurrences with constant coefficients, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

Crossrefs

Cf. A000312 (n^n), A056849 (mod 10), A174824.

Programs

Mathematica

Table[PowerMod[n,n,100],{n,0,70}] (* Harvey P. Dale, Aug 13 2023 *)

Python

def a(n): return pow(n, n, 100)
print([a(n) for n in range(101)]) # Michael S. Branicky, Sep 26 2021

Formula

For n >= 101, a(n) = a(n-100), i.e., cyclic with period A174824(100) = 100, disregarding a(0). - Michael S. Branicky, Sep 26 2021