A348644 a(n) = (18*n + 1)*(24*n + 1)*(144*n + 11).
11, 73625, 542087, 1778645, 4156547, 8049041, 13829375, 21870797, 32546555, 46229897, 63294071, 84112325, 109057907, 138504065, 172824047, 212391101, 257578475, 308759417, 366307175, 430594997, 501996131, 580883825, 667631327, 762611885, 866198747, 978765161, 1100684375
Offset: 0
Links
- Ajai Choudhry, A diophantine problem concerning third order matrices, arXiv:2110.12643 [math.NT], 2021.
- Wikipedia, Unimodular matrix.
- Index entries for linear recurrences with constant coefficients, signature (4,-6,4,-1).
Programs
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PARI
a(n) = (18*n + 1)*(24*n + 1)*(144*n + 11);
Formula
From Elmo R. Oliveira, Sep 03 2025: (Start)
G.f.: (11 + 73581*x + 247653*x^2 + 52003*x^3)/(x-1)^4.
E.g.f.: (11 + 73614*x + 197424*x^2 + 62208*x^3)*exp(x).
a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4). (End)
Comments