A349245 Minimal sequence of single-tile sliding moves that progressively transpose elements 0 through k (k = 1, 2, 3, ...) of the infinite square matrix, cf. comments for details.
1, 4, 2, 1, 4, 2, 1, 4, 2, 3, 7, 12, 8, 5, 4, 1, 3, 2, 1, 3, 5, 4, 3, 1, 2, 5, 4, 8, 12, 7, 5, 2, 1, 3, 8, 13, 9, 8, 3, 1, 2, 5, 6, 11, 7, 6, 5, 2, 1, 4, 6, 12, 13, 6, 4, 3, 6, 9, 8, 6, 3, 1, 2, 4, 12, 7, 17, 13, 7, 12, 9, 7, 12, 9, 4, 2, 1, 3, 7, 8, 18, 12, 8, 18, 12, 24, 13, 17, 9
Offset: 1
Examples
Starting from the initial configuration (cf. comments), the first possible move "1" means to slide the 1 from row 1, column 2 to the "empty square" 0 at (1,1); then move "4" slides the 4 one up, and move "2" slides the 2 to the right: 0 1 3 ... (1) 1 0 3 ... (4) 1 4 3 ... (2) 1 4 3 ... 2 4 7 ... ==> 2 4 7 ... ==> 2 0 7 ... ==> 0 2 7 ... ... ... ... ... ... ... ... ... ... ... ... ... The next move, 1, will place that tile in its final position (row 2, column 1): (1) 0 4 3 ... ==> 1 2 7 ... ... ... ... Given that the 0 is also in its final position (1,1), this achieves what we call goal [1]. Now further moves 4 and 2 would move the 2 in its final position (1,2), so {1, 2} are in their final position, but 0 isn't. (This is called goal (2) in comments.) However, to achieve goal [2] with also 0 in its initial position (row 1, column 1), in a minimum number of moves, one has to proceed differently: see a(4..18). Formatted as an irregular table with rows ending with achieved goals [1], [2], [3], ... the sequence reads: row 1: [1, 4, 2, 1] \\ here {0, 1} are at their final position row 2: [4, 2, 1, 4, 2, 3, 7, 12, 8, 5, 4, 1, 3, 2] \\ here {0, 1, 2} are "done" row 3: [1, 3, 5, 4, 3, 1] \\ here {0, 1, 2, 3} are in their final position row 4: [2, 5, 4, 8, 12, 7, 5, 2] \\ now {0, ..., 4} are in their final position row 5: [1, 3, 8, 13, 9, 8, 3, 1] \\ now {0, ..., 5} are in their final position row 6: [2, 5, 6, 11, 7, 6, 5, 2, 1, 4, 6, 12, 13, 6, 4, 3, 6, 9, 8, 6, 3, 1] row 7: [2, 4, 12, 7, 17, 13, 7, 12, 9, 7, 12, 9, 4, 2] row 8: [1, 3, 7, 8, 18, 12, 8, 18, 12, 24, 13, 17, 9, 8, 18, 7, 3, 1] row 9: [2, 4, 8, 18, 17, 23, 16, 10, 11, 9, 18, 8, 4, 2]
Links
- M. F. Hasler, in reply to J. Propp, Infinite sliding block puzzle, math-fun discussion list, Nov. 3, 2021
- Wikipedia, 15 puzzle, retrieved Nov. 2021
Comments