A349707 Numbers that are congruent to {0, 1, 4, 6, 8, 10, 11} (mod 12).
0, 1, 4, 6, 8, 10, 11, 12, 13, 16, 18, 20, 22, 23, 24, 25, 28, 30, 32, 34, 35, 36, 37, 40, 42, 44, 46, 47, 48, 49, 52, 54, 56, 58, 59, 60, 61, 64, 66, 68, 70, 71, 72, 73, 76, 78, 80, 82, 83, 84, 85, 88, 90, 92, 94, 95, 96, 97, 100, 102, 104, 106, 107, 108, 109
Offset: 1
Links
- Wikipedia, Enigmatic scale.
- Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,0,0,1,-1).
Crossrefs
Cf. A083028.
Programs
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Mathematica
upto=200;Select[Range[0,upto],MemberQ[{0,1,4,6,8,10,11},Mod[#,12]]&] (* Paolo Xausa, Nov 30 2021 *) nterms=100;LinearRecurrence[{1,0,0,0,0,0,1,-1},{0,1,4,6,8,10,11,12},nterms] (* Paolo Xausa, Nov 30 2021 *)
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Python
def a(n): return 12*((n-1)//7) + [0, 1, 4, 6, 8, 10, 11][(n-1)%7] print([a(n) for n in range(1, 66)]) # Michael S. Branicky, Dec 02 2021
Formula
G.f.: x^2*(1 + 3*x + 2*x^2 + 2*x^3 + 2*x^4 + x^5 + x^6)/((1 - x)^2*(1 + x + x^2 + x^3 + x^4 + x^5 + x^6)). - Stefano Spezia, Dec 01 2021
a(n) = a(n-7) + 12 for n >= 8. - Michael S. Branicky, Dec 02 2021
Comments