cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A350050 a(n) = (2*n^4 - 6*(-1)^n*n^2 - 2*n^2 + 3*(-1)^n - 3)/96.

Original entry on oeis.org

0, 0, 0, 2, 4, 14, 24, 52, 80, 140, 200, 310, 420, 602, 784, 1064, 1344, 1752, 2160, 2730, 3300, 4070, 4840, 5852, 6864, 8164, 9464, 11102, 12740, 14770, 16800, 19280, 21760, 24752, 27744, 31314, 34884, 39102, 43320, 48260, 53200, 58940, 64680, 71302, 77924, 85514
Offset: 0

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Author

Stefano Spezia, Dec 11 2021

Keywords

Comments

Definitions: (Start)
The k-th exterior power of a vector space V of dimension n is a vector subspace spanned by elements, called k-vectors, that are the exterior product of k vectors v_i in V.
Given a square matrix A that describes the vectors v_i in terms of a basis of V, the k-th exterior power of the matrix A is the matrix that represents the k-vectors in terms of the basis of V. (End)
Conjectures: (Start)
For n > 1, a(n) is the absolute value of the trace of the 2nd exterior power of an n X n square matrix A(n) defined as A[i,j,n] = n - abs((n + 1)/2 - j) - abs((n + 1)/2 - i) (see A349107). Equivalently, a(n) is the absolute value of the coefficient of the term [x^(n-2)] in the characteristic polynomial of the matrix A(n), or the absolute value of the sum of all principal minors of A(n) of size 2.
For k > 2, the trace of the k-th exterior power of the matrix A(n) is equal to zero. (End)
The same conjectures hold for an n X n square matrix A(n) defined as A[i,j,n] = (n mod 2) + abs((n + 1)/2 - j) + abs((n + 1)/2 - i) (see A349108).

Crossrefs

Cf. A000982 (trace of matrix A(n)), A317614 (elements sum of matrix A(n)), A349107, A349108.

Programs

  • Mathematica
    Table[(2*n^4-6*(-1)^n*n^2-2*n^2+3*(-1)^n-3)/96,{n,0,45}]
  • PARI
    a(n) = (2*n^4 - 6*(-1)^n*n^2 - 2*n^2 + 3*(-1)^n - 3)/96 \\ Winston de Greef, Jan 28 2024

Formula

O.g.f.: 2*x^3*(1 + x^2)/((1 - x)^5*(1 + x)^3).
E.g.f.: (x*(x^3 + 6*x^2 + 3*x + 3)*cosh(x) + (x^4 + 6*x^3 + 9*x^2 - 3*x - 3)*sinh(x))/48.
a(n) = 2*a(n-1) + 2*a(n-2) - 6*a(n-3) + 6*a(n-5) - 2*a(n-6) - 2*a(n-7) + a(n-8) for n > 7.
a(n) = A338429(n-2)/2 for n > 2.
a(2*n-1) = 2*A006325(n).
a(2*n) = A112742(n).
Sum_{n>2} 1/a(n) = (45 - 2*Pi^2 - 4*sqrt(3)*Pi*tanh(sqrt(3)*Pi/2))/4 = 0.920755957767250147865...