A350311 Replace 2^k in the binary expansion of n with A000930(k+2), Narayana's cows sequence.
0, 1, 2, 3, 3, 4, 5, 6, 4, 5, 6, 7, 7, 8, 9, 10, 6, 7, 8, 9, 9, 10, 11, 12, 10, 11, 12, 13, 13, 14, 15, 16, 9, 10, 11, 12, 12, 13, 14, 15, 13, 14, 15, 16, 16, 17, 18, 19, 15, 16, 17, 18, 18, 19, 20, 21, 19, 20, 21, 22, 22, 23, 24, 25, 13, 14, 15, 16, 16, 17
Offset: 0
Links
- Rémy Sigrist, Table of n, a(n) for n = 0..8191
Programs
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Maple
b:= (n, i, j, k)->`if`(n=0, 0, k*irem(n, 2, 'q')+b(q, j, k, i+k)): a:= n-> b(n, 1$3): seq(a(n), n=0..100); # Alois P. Heinz, Jan 26 2022
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PARI
my(p=Mod('x,'x^3-'x^2-1)); a(n) = vecsum(Vec(lift(subst(Pol(binary(n))*'x^2,'x,p)))); \\ Kevin Ryde, Dec 26 2021
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Python
def Interpretation(n): f0, f1, f2, r = 1, 1, 1, 0 while n > 0: if n%2 == 1: r = r+f0 n, f0, f1, f2 = n//2, f0+f2, f0, f1 return r n = 0 while n <= 69: print(Interpretation(n), end = ", ") n += 1
Comments