cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A350689 a(n) = n*(1 - (-1)^n - 2*(3 + (-1)^n)*n^2 + 2*n^4)/384.

Original entry on oeis.org

0, 0, 0, 1, 4, 15, 36, 84, 160, 300, 500, 825, 1260, 1911, 2744, 3920, 5376, 7344, 9720, 12825, 16500, 21175, 26620, 33396, 41184, 50700, 61516, 74529, 89180, 106575, 126000, 148800, 174080, 203456, 235824, 273105, 313956, 360639, 411540, 469300, 532000, 602700
Offset: 0

Views

Author

Stefano Spezia, Jan 12 2022

Keywords

Comments

Definitions: (Start)
The k-th exterior power of a vector space V of dimension n is a vector subspace spanned by elements, called k-vectors, that are the exterior product of k vectors v_i in V.
Given a square matrix A that describes the vectors v_i in terms of a basis of V, the k-th exterior power of the matrix A is the matrix that represents the k-vectors in terms of the basis of V. (End)
Conjectures: (Start)
For n > 1, a(n) is the absolute value of the trace of the 3rd exterior power of an n X n square matrix M(n) defined as M[i,j] = floor((j - i + 1)/2). Equivalently, a(n) is the absolute value of the coefficient of the term [x^(n-3)] in the characteristic polynomial of the matrix M(n), or the absolute value of the sum of all principal minors of M(n) of size 3.
For k > 3, the trace of the k-th exterior power of the matrix M(n) is equal to zero. (End)
The matrix M(n) is the n-th principal submatrix of the array A010751.

Crossrefs

Cf. A002620 (elements sum of the matrix M(n)), A010751, A108674, A350549 (permanent of the matrix M(n)).

Programs

  • Mathematica
    Table[n(1 - (-1)^n - 2*(3 + (-1)^n)n^2 + 2n^4)/384,{n,0,41}]

Formula

O.g.f.: x^3*(1 + 2*x + 4*x^2 + 2*x^3 + x^4)/((1 - x)^6*(1 + x)^4).
E.g.f.: x*(x*(x^3 + 10*x^2 + 23*x + 3)*cosh(x) + (x^4 + 10*x^3 + 21*x^2 + 9*x - 3)*sinh(x))/192.
a(n) = 2*a(n-1) + 3*a(n-2) - 8*a(n-3) - 2*a(n-4) + 12*a(n-5) - 2*a(n-6) - 8*a(n-7) + 3*a(n-8) + 2*a(n-9) - a(n-10) for n > 9.
a(2*n+1) = A108674(n-1) for n > 0.
Sum_{n>2} 1/a(n) = 192*log(2) - 6*zeta(3) - 249/2 = 1.371917248551933695710...