A351200 Number of patterns of length n with all distinct runs.
1, 1, 3, 11, 53, 305, 2051, 15731, 135697, 1300869, 13726431, 158137851, 1975599321, 26607158781, 384347911211, 5928465081703, 97262304328573, 1691274884085061, 31073791192091251, 601539400910369671, 12238270940611270161, 261071590963047040241
Offset: 0
Keywords
Examples
The a(1) = 1 through a(3) = 11 patterns: (1) (1,1) (1,1,1) (1,2) (1,1,2) (2,1) (1,2,2) (1,2,3) (1,3,2) (2,1,1) (2,1,3) (2,2,1) (2,3,1) (3,1,2) (3,2,1) The complement for n = 3 counts the two patterns (1,2,1) and (2,1,2).
Links
- Andrew Howroyd, Table of n, a(n) for n = 0..200
- Mathematics Stack Exchange, What is a sequence run? (answered 2011-12-01)
Crossrefs
The version for run-lengths instead of runs is A351292.
A005811 counts runs in binary expansion.
A032011 counts patterns with distinct multiplicities.
A044813 lists numbers whose binary expansion has distinct run-lengths.
A131689 counts patterns by number of distinct parts.
A297770 counts distinct runs in binary expansion.
Counting words with all distinct runs:
- A351202 = permutations of prime factors.
- A351642 = word structures.
Row sums of A351640.
Programs
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Mathematica
allnorm[n_]:=If[n<=0,{{}},Function[s,Array[Count[s,y_/;y<=#]+1&,n]] /@Subsets[Range[n-1]+1]]; Table[Length[Select[Join@@Permutations/@allnorm[n],UnsameQ@@Split[#]&]],{n,0,6}]
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PARI
\\ here LahI is A111596 as row polynomials. LahI(n,y)={sum(k=1, n, y^k*(-1)^(n-k)*(n!/k!)*binomial(n-1, k-1))} S(n)={my(p=prod(k=1, n, 1 + y*x^k + O(x*x^n))); 1 + sum(i=1, (sqrtint(8*n+1)-1)\2, polcoef(p,i,y)*LahI(i,y))} R(q)={[subst(serlaplace(p), y, 1) | p<-Vec(q)]} seq(n)={my(q=S(n)); concat([1], sum(k=1, n, R(q^k-1)*sum(r=k, n, binomial(r, k)*(-1)^(r-k)) ))} \\ Andrew Howroyd, Feb 12 2022
Extensions
Terms a(10) and beyond from Andrew Howroyd, Feb 12 2022
Comments