A352487 Excedance set of A122111. Numbers k < A122111(k), where A122111 represents partition conjugation using Heinz numbers.
3, 5, 7, 10, 11, 13, 14, 15, 17, 19, 21, 22, 23, 25, 26, 28, 29, 31, 33, 34, 35, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 49, 51, 52, 53, 55, 57, 58, 59, 61, 62, 63, 65, 66, 67, 68, 69, 70, 71, 73, 74, 76, 77, 78, 79, 82, 83, 85, 86, 87, 88, 89, 91, 92, 93, 94
Offset: 1
Keywords
Examples
The terms together with their prime indices begin: 3: (2) 5: (3) 7: (4) 10: (3,1) 11: (5) 13: (6) 14: (4,1) 15: (3,2) 17: (7) 19: (8) 21: (4,2) 22: (5,1) 23: (9) 25: (3,3) 26: (6,1) 28: (4,1,1) For example, the partition (4,1,1) has Heinz number 28 and its conjugate (3,1,1,1) has Heinz number 40, and 28 < 40, so 28 is in the sequence, and 40 is not.
Links
- Alois P. Heinz, Table of n, a(n) for n = 1..10000
- Richard Ehrenborg and Einar Steingrímsson, The Excedance Set of a Permutation, Advances in Applied Mathematics 24, (2000), 284-299.
- MathOverflow, Why 'excedances' of permutations? [closed].
Crossrefs
Programs
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Mathematica
primeMS[n_]:=If[n==1,{},Flatten[Cases[FactorInteger[n],{p_,k_}:>Table[PrimePi[p],{k}]]]]; conj[y_]:=If[Length[y]==0,y,Table[Length[Select[y,#>=k&]],{k,1,Max[y]}]]; Select[Range[100],#
Formula
a(n) < A122111(a(n)).
Comments