cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A353590 Lexicographically earliest permutation of the nonnegative integers filling an infinite square array by falling antidiagonals so that the elements on any 2 X 2 square sum to a square.

Original entry on oeis.org

0, 1, 2, 3, 6, 4, 5, 15, 13, 7, 8, 26, 30, 12, 9, 10, 25, 29, 45, 21, 11, 14, 38, 20, 17, 22, 23, 16, 18, 19, 61, 34, 37, 55, 31, 24, 27, 49, 51, 54, 33, 82, 35, 50, 28, 32, 75, 77, 59, 48, 44, 53, 80, 42, 36, 39, 62, 88, 69, 64, 71, 46, 57, 84, 63, 40, 41, 92, 99, 90, 97, 73, 95
Offset: 0

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Author

M. F. Hasler, May 29 2022

Keywords

Comments

In A337115 the infinite 2D lattice is filled along a square spiral satisfying the same constraint of 2 X 2 squares adding up to squares.

Examples

			The square array starts:
   0   1   3   5   8  10  14  18  27  32  ...
   2   6  15  26  25  38  19  49  75  ...
   4  13  30  29  20  61  51  77  ...
   7  12  45  17  34  54  59  ...
   9  21  22  37  33  48  ...
  11  23  55  82  44  ...
  16  31  35  53  ...
  24  50  80  ...
  28  42  ...
  36  ...
  ...
a(4) is in the second row and column. It must sum up with a(0) = 0, a(1) = 1 and a(2) = 2 to a square, the smallest possible solution is a(4) = 6.
Similarly, a(7) which is on the second row, third column, must sum up with a(1) = 1 (above to the left), a(3) = 3 (above) and a(4) = 6 (to the left) to a square; the smallest solution is a(7) = 15.
		

Crossrefs

Cf. A000290 (the squares), A337115 (same idea with square spiral instead of array by antidiagonals), A353591 (same idea with primes instead of squares).

Programs

  • PARI
    A353590_upto(N, M=Map(), r,c, U=[-1])={vector(N, i, if(r && c, my(s=mapget(M,[r-1,c-1])+mapget(M,[r-1,c])+mapget(M,[r,c-1]), m=sqrtint(s)+1); while(setsearch(U, N=m^2-s)||N<=U[1], m+=1); U=setunion(U, [N]), N=U[1]+=1); mapput(M,[r,c], N); if(c, c--;r++, r=!c=r+1); while(#U>2 && U[2]==U[1]+1, U=U[^1]); N)}
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