A353619
Side a of primitive integer-sided triangles (a, b, c) whose angle B = 3*C.
Original entry on oeis.org
3, 35, 119, 112, 279, 20, 253, 539, 552, 91, 923, 533, 476, 1455, 224, 1504, 17, 799, 2159, 1513, 1476, 437, 1387, 3059, 2261, 1240, 3160, 4179, 2163, 748, 3212, 391, 1817, 5543, 3151, 4393, 5712, 1175, 2825, 7175, 5825, 2548, 5876, 189, 9099, 4077, 5859, 1736, 9352, 5768, 1189
Offset: 1
According to inequalities between a, b, c, there exist 3 types of such triangles:
a < c < b with the smallest side a = 3 of the first triple (3, 10, 8).
c < a < b with the middle side a = 35 of the 2nd triple (35, 48, 27).
c < b < a with the largest side a = 539 of the 8th triple (539, 510, 216), the first of this type.
- The IMO Compendium, Problem 1, 46th Czech and Slovak Mathematical Olympiad 1997.
Cf.
A343064 (similar, but with B = 2*C).
-
for b from 4 to 9000 do
for q from 2 to floor((b-1)^(1/3)) do
a := (b-q^3) * sqrt(1+b/q^3);
if a= floor(a) and q^3 < b and igcd(a,b,q)=1 and (b-q^3) < a and a < b+q^3 then print(a); end if;
end do;
end do;
A353620
Side b of primitive integer-sided triangles (a, b, c) whose angle B = 3*C.
Original entry on oeis.org
10, 48, 132, 195, 280, 357, 504, 510, 665, 792, 840, 840, 1035, 1288, 1485, 1575, 1740, 1848, 1872, 1890, 2233, 2496, 2604, 2610, 2640, 3003, 3069, 3520, 3536, 3885, 4095, 4368, 4560, 4620, 4662, 4680, 5291, 5712, 5904, 5928, 6006, 6579, 6765, 6992, 7462, 7480, 7568, 8037, 8385, 8415, 8820
Offset: 1
According to inequalities between a, b, c, there exist 3 types of such triangles:
a < c < b with the largest side b = 10 of the first triple (3, 10, 8).
c < a < b with the largest side b = 48 of the 2nd triple (35, 48, 27).
c < b < a with the middle side b = 510 of the 8th triple (539, 510, 216), the first of this type.
The first side b for which there exist two distinct triangles with B = 3*C is for a(11) = a(12) = 840, and these sides b belong respectively to triples (923, 840, 343) and (533, 840, 512).
- The IMO Compendium, Problem 1, 46th Czech and Slovak Mathematical Olympiad 1997.
Cf.
A343065 (similar, but with B = 2*C).
-
for b from 4 to 9000 do
for q from 2 to floor((b-1)^(1/3)) do
a := (b-q^3) * sqrt(1+b/q^3);
if a= floor(a) and q^3 < b and igcd(a,b,q)=1 and (b-q^3) < a and a < b+q^3 then print(b); end if;
end do;
end do;
A353621
Side c of primitive integer-sided triangles (a, b, c) whose angle B = 3*C.
Original entry on oeis.org
8, 27, 64, 125, 125, 343, 343, 216, 343, 729, 343, 512, 729, 512, 1331, 729, 1728, 1331, 729, 1000, 1331, 2197, 1728, 1000, 1331, 2197, 1331, 1331, 2197, 3375, 2197, 4096, 3375, 1728, 2744, 2197, 2197, 4913, 4096, 2197, 2744, 4913, 3375, 6859, 2744, 4913, 4096, 6859, 3375, 4913, 8000
Offset: 1
According to inequalities between a, b, c, there exist 3 types of such triangles:
a < c < b with the middle side c = 8 of the first triple (3, 10, 8).
c < a < b with the smallest side c = 27 of the 2nd triple (35, 48, 27).
c < b < a with the smallest side c = 216 of the 8th triple (539, 510, 216), the first of this type.
The smallest side c for which there exist two distinct triangles with B = 3*C is for a(4) = a(5) = 125, and these sides c belong respectively to triples (112, 195, 125) and (279, 280, 125).
- The IMO Compendium, Problem 1, 46th Czech and Slovak Mathematical Olympiad 1997.
Cf.
A343066 (similar, but with B = 2*C).
-
for b from 4 to 9000 do
for q from 2 to floor((b-1)^(1/3)) do
a := (b-q^3) * sqrt(1+b/q^3);
if a= floor(a) and q^3 < b and igcd(a,b,q)=1 and (b-q^3) < a and a < b+q^3 then print(q^3); end if;
end do;
end do;
A353622
Perimeter of integer-sided primitive triangles (a, b, c) whose angle B = 3*C.
Original entry on oeis.org
21, 110, 315, 432, 684, 720, 1100, 1265, 1560, 1612, 2106, 1885, 2240, 3255, 3040, 3808, 3485, 3978, 4760, 4403, 5040, 5130, 5719, 6669, 6232, 6440, 7560, 9030, 7896, 8008, 9504, 8855, 9752, 11891, 10557, 11270, 13200, 11800, 12825, 15300, 14575, 14040, 16016
Offset: 1
According to inequalities between a, b, c, there exist 3 types of such triangles:
a(1) = 21 with a < c < b for the first triple (3, 10, 8);
a(2) = 110 with c < a < b for the 2nd triple (35, 48, 27);
a(8) = 1265 with c < b < a for the 8th triple (539, 510, 216).
- The IMO Compendium, Problem 1, 46th Czech and Slovak Mathematical Olympiad 1997.
Cf.
A343067 (similar, but with B = 2*C).
-
for b from 4 to 9000 do
for q from 2 to floor((b-1)^(1/3)) do
a := (b-q^3) * sqrt(1+b/q^3);
if a=floor(a) and q^3 < b and igcd(a,b,q)=1 and b-q^3 < a and a < b+q^3 then
print(a+b+q^3);
end if;
end do;
end do;
-
lista(nn) = {for (b = 4 , nn, for (q = 2 , sqrtnint(b-1, 3), if (issquare(z=1+b/q^3), a = (b-q^3) * sqrtint(numerator(z))/sqrtint(denominator(z)); if ((q^3 < b) && (gcd([a, b, q])==1) && (b-q^3 < a) && (a < b+q^3), print1(a+b+q^3, ", ");););););} \\ Michel Marcus, May 11 2022
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