A358028 Primes p = prime(9*t+1) such that the 9 consecutive primes prime(9*t+1) .. prime(9*t+9) arranged in a 3 X 3 array have at least 2 equal sums along the rows, columns or main diagonals.
2, 29, 67, 107, 157, 257, 311, 367, 541, 599, 709, 769, 829, 967, 1021, 1549, 1741, 1811, 1879, 1973, 2609, 2677, 3019, 3541, 3677, 4051, 4217, 4271, 4517, 4597, 4663, 4931, 5227, 5303, 5399, 5449, 5623, 5683, 5839, 6079, 6229, 6301, 6361, 6451, 6949, 7253, 7351, 7477, 7537, 7589, 7673
Offset: 1
Keywords
Examples
2 is a term since its block of 9 primes is | 2 | 3 | 5 | | 7 | 11 | 13 | | 17 | 19 | 23 | which has among its lines (3 + 11 + 19) = (17 + 11 + 5). 67 is a term since its block of 9 primes (the 3rd block) is 67..103, | 67 | 71 | 73 | | 79 | 83 | 89 | | 97 | 101| 103| which has 67+83+103 = 97+83+73.
Programs
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Mathematica
a = {} row = {{1, 4, 7}, {2, 5, 8}, {3, 6, 9}}; col = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}; dia = {{1, 3}, {5, 5}, {9, 7}}; Duplicates[l_] := Block[{i}, i[n_] := (i[n] = n; Unevaluated@Sequence[]); i /@ l] Do[If[Duplicates[ Flatten[{Total[Prime[row + 9 n]], Total[Prime[col + 9 n]], Total[Prime[dia + 9 n]]}]] != {}, AppendTo[a, Prime[9 n + 1]]], {n, 0, 110}] a (* Gerry Martens, Nov 12 2022 *)
Extensions
More terms from Gerry Martens, Nov 12 2022
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