A359347 Roots of reversible pandigital square numbers.
1111103, 3011111, 11110922, 11111003, 11111030, 11111120, 11111210, 11112110, 11211110, 12111110, 21111110, 21911111, 30011111, 30111110, 101110922, 101111112, 101111121, 101111211, 102111111, 110109212, 110911211, 110921111, 111109220, 111110030, 111110103
Offset: 1
Examples
1111103^2 = 1234549876609 <~> 9066789454321 = 3011111^2. 11110922^2 = 123452587690084 <~> 480096785254321 = 21911111^2.
Links
- Martin Renner, Table of n, a(n) for n = 1..458
Programs
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Python
from math import isqrt from itertools import count, islice def c(n): return len(set(s:=str(n)))==10 and isqrt(r:=int(s[::-1]))**2==r def agen(): yield from (k for k in count(10**6) if c(k*k)) print(list(islice(agen(), 25))) # Michael S. Branicky, Dec 27 2022
Formula
a(n) = sqrt(A359346(n)).
Comments