A359498 a(n) = ((2*n+1)^8 - 1)/32.
0, 205, 12207, 180150, 1345210, 6698715, 25491585, 80090332, 217992420, 530736345, 1181964355, 2447218290, 4768371582, 8825923015, 15632700405, 26652844920, 43950269320, 70371105957, 109764982935, 167250289390, 249528913410, 365256258675, 525472668457, 744102708180
Offset: 0
Links
- Jianing Song, Table of n, a(n) for n = 0..10000
- Index entries for linear recurrences with constant coefficients, signature (9,-36,84,-126,126,-84,36,-9,1).
Crossrefs
Programs
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Mathematica
((2*Range[0, 25] + 1)^8 - 1)/32 (* Paolo Xausa, Jan 23 2025 *)
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PARI
a(n) = ((2*n+1)^8 - 1)/32
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Python
def A359498(n): return ((n<<1)+1)**8-1>>5 # Chai Wah Wu, Jan 15 2023
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