A360246 Numbers for which the prime indices do not have the same mean as the distinct prime indices.

12, 18, 20, 24, 28, 40, 44, 45, 48, 50, 52, 54, 56, 60, 63, 68, 72, 75, 76, 80, 84, 88, 92, 96, 98, 99, 104, 108, 112, 116, 117, 120, 124, 126, 132, 135, 136, 140, 144, 147, 148, 150, 152, 153, 156, 160, 162, 164, 168, 171, 172, 175, 176, 180, 184, 188, 189

Offset: 1

Author

Gus Wiseman, Feb 07 2023

Keywords

• nonn

Comments

First differs from A242416 in having 126.

Contains no squarefree numbers or perfect powers.

A prime index of n is a number m such that prime(m) divides n. The multiset of prime indices of n is row n of A112798.

Examples

			The terms together with their prime indices begin:
   12: {1,1,2}
   18: {1,2,2}
   20: {1,1,3}
   24: {1,1,1,2}
   28: {1,1,4}
   40: {1,1,1,3}
   44: {1,1,5}
   45: {2,2,3}
   48: {1,1,1,1,2}
   50: {1,3,3}
   52: {1,1,6}
   54: {1,2,2,2}
   56: {1,1,1,4}
   60: {1,1,2,3}
   63: {2,2,4}
   68: {1,1,7}
   72: {1,1,1,2,2}
The prime indices of 126 are {1,2,2,4} with mean 9/4 and distinct prime indices {1,2,4} with mean 7/3, so 126 is in the sequence.
		

Crossrefs

Signature instead of parts: complement A324570, counted by A114638.

Signature instead of distinct parts: complement A359903, counted by A360068.

These partitions are counted by A360242.

The complement is A360247, counted by A360243.

For median we have A360248, counted by A360244 (complement A360245).

Union of A360252 and A360253, counted by A360250 and A360251.

A058398 counts partitions by mean, also A327482.

A088529/A088530 gives mean of prime signature (A124010).

A112798 lists prime indices, length A001222, sum A056239.

A316413 = numbers whose prime indices have integer mean, distinct A326621.

A326567/A326568 gives mean of prime indices.

A326619/A326620 gives mean of distinct prime indices.

Cf. A000975, A051293, A067340, A067538, A360005, A360241.

Programs

Mathematica

prix[n_]:=If[n==1,{},Flatten[Cases[FactorInteger[n],{p_,k_}:>Table[PrimePi[p],{k}]]]];
Select[Range[100],Mean[prix[#]]!=Mean[Union[prix[#]]]&]