A362557 Start with first term 0, then add paired terms counting every preceding term up to the largest term so far and loop back to 0 after every pair has been counted.
0, 1, 0, 1, 1, 2, 0, 3, 1, 1, 2, 1, 3, 3, 0, 6, 1, 2, 2, 3, 3, 1, 6, 4, 0, 8, 1, 4, 2, 5, 3, 2, 4, 1, 5, 2, 6, 1, 8, 5, 0, 11, 1, 7, 2, 6, 3, 3, 4, 3, 5, 4, 6, 1, 7, 2, 8, 1, 11, 6, 0, 14, 1, 9, 2, 9, 3, 5, 4, 5, 5, 6, 6, 2, 7, 3, 8, 2, 9, 2, 11, 1, 14, 7, 0
Offset: 1
Examples
Write "0". There is now "1 0". Now there is "1 1". We can't find any terms greater than 1, so we recheck the sequence for 0s and find "2 0(s)". Listing these terms in the order read out loud yields the sequence "0, 1, 0, 1, 1, 2, 0, ...".
Programs
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PARI
seq(n)={my(L=List([0]), m=0, k=0); while(#L
t==k, L)); if(c, listput(L,c); listput(L,k); m=max(m,c)); k=if(k==m, 0, k+1)); Vec(L)} \\ Andrew Howroyd, May 02 2023
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