A364513 Square array read by ascending antidiagonals: T(n,k) = [x^k] (1 - x)^(2*k) * Legendre_P(n*k-1, (1 + x)/(1 - x)) for n, k >= 0.
1, 1, -2, 1, -2, 6, 1, 0, 0, -20, 1, 4, 0, 16, 70, 1, 10, 126, 0, 0, -252, 1, 18, 594, 4900, 0, -252, 924, 1, 28, 1716, 44200, 209950, 0, 0, -3432, 1, 40, 3900, 205920, 3640210, 9513504, 0, 4800, 12870, 1, 54, 7650, 685216, 27386100, 317678760, 447103440, 0, 0, -48620, 1, 70, 13566, 1847560, 133501500, 3861534768, 28782923400, 21558808128, 0, -100100, 184756
Offset: 0
Examples
Square array begins: n\k| 0 1 2 3 4 5 - + - - - - - - - - - - - - - - - - - - - - - - - - - - - 0 | 1 -2 6 -20 70 -252 ... (see A000984) 1 | 1 -2 0 16 0 -252 ... A364514 2 | 1 0 0 0 0 0 3 | 1 4 126 4900 209950 9513504 ... (1/3)*A352651 4 | 1 10 594 44200 3640210 317678760 ... A364515 5 | 1 18 1716 205920 27386100 3861534768 ... (3/5)*A352652 6 | 1 28 3900 685216 133501500 27583083528 ... A364516 7 | 1 40 7650 1847560 494944450 140625140040 ... A364517
Links
- J. W. Bober, Factorial ratios, hypergeometric series, and a family of step functions, arXiv:0709.1977 [math.NT], 2007; J. London Math. Soc. (2) 79 2009, 422-444.
- K. Soundararajan, Integral factorial ratios: irreducible examples with height larger than 1, Phil. Trans. Royal Soc., A378: 2018044, 2019.
- Wikipedia, Dixon's identity
Crossrefs
Programs
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Maple
T(n,k) := coeff(series( (1 - x)^(2*k) * LegendreP(n*k-1, (1 + x)/(1 - x)), x, 11), x, k): # display as a square array seq(print(seq(T(n, k), k = 0..10)), n = 0..10); # display as a sequence seq(seq(T(n-k, k), k = 0..n), n = 0..10);
Formula
T(n,k) = Sum_{i = 0..k} binomial(n*k-1, k-i)^2 * binomial((n-2)*k+i-2, i).
T(n,1) = 1 for all n and for n >= 2 and k >= 1, T(n,k) = binomial((k*n-1), k)^2 * hypergeom([a, b, b], [1 + a - b, 1 + a - b], 1), where a = (n - 2)*k - 1 and b = -k.
For n >= 3 and k >= 1, T(n,k) = ((n*k - 1))! * ( ((n+2)*k - 1)/2 )! * ( ((n-2)*k - 1)/2 )! / ( k!^2 * ((n-2)*k - 1)! * ((n*k - 1)/2)!^2 ) by Dixon's 3F2 summation theorem, where fractional factorials are defined in terms of the gamma function.
For n >= 3 and k >= 1, T(n,k) = (n-2)/n * ((n+2)*k)!*(n*k/2)!^2 / ( ((n+2)*k/2)! * (n*k)! * ((n-2)*k/2)! * k!^2 ).
Comments