A365105 Continued fraction expansion of 1/(2+3/(4+5/(6+7/(...)))) = A113014.
0, 2, 1, 1, 1, 2, 1, 2, 10, 2, 2, 66, 1, 1, 13, 66, 9, 5, 8, 1, 9, 1, 1, 1, 5, 2, 2, 3, 1, 1, 1, 16, 99, 6, 1, 5, 1, 2, 1, 55, 2, 2, 1, 1, 6, 4, 1, 1, 1, 40, 1, 1, 1, 6, 14, 7, 9, 1, 1, 2, 3, 2, 2, 2, 1, 1, 2, 7, 12, 1, 2, 2, 1, 4, 2, 4, 2, 1, 3, 2, 1, 10, 7, 1, 4, 1, 119, 1, 1, 1, 3, 5, 2, 12, 1
Offset: 0
Examples
1/(2+1/(1+1/(1+1/(1+1/(2+1/(...)))))) = 1/(2+3/(4+5/(6+7/(...)))).
Programs
-
Mathematica
A365105 = ContinuedFraction[Sqrt[2*E/Pi]/Erfi[1/Sqrt[2]]-1,#]&;
Comments