A365675 a(n) = Sum_{k=0..n} p(k) where the p(k) are the partial sums of row n of A365676.

1, 1, 4, 8, 18, 30, 58, 90, 153, 233, 365, 533, 806, 1142, 1652, 2308, 3243, 4431, 6103, 8203, 11080, 14710, 19540, 25612, 33612, 43570, 56476, 72548, 93080, 118490, 150699, 190315, 240046, 301042, 376887, 469515, 583993, 723073, 893815, 1100615, 1352888

Offset: 0

Author

Peter Luschny, Sep 16 2023

Keywords

• nonn

Comments

If one reverses row n in the definition formula before accumulating, one gets A000070.

Crossrefs

Cf. A365676, A000070.

Programs

Python

# Using function A365676Row from A365676.
from itertools import accumulate
def A365675List(size: int) -> list[int]:
    return [sum(accumulate(A365676Row(n))) for n in range(size)]
print(A365675List(41))