A368519 Irregular triangular array T, read by rows: T(n,k) = number of sums |x-y|+|y-z| = k, where x,y,z are in {1,2,...,n} and x < z.
2, 4, 3, 2, 6, 6, 8, 2, 2, 8, 9, 14, 9, 6, 2, 2, 10, 12, 20, 16, 16, 6, 6, 2, 2, 12, 15, 26, 23, 26, 17, 12, 6, 6, 2, 2, 14, 18, 32, 30, 36, 28, 26, 12, 12, 6, 6, 2, 2, 16, 21, 38, 37, 46, 39, 40, 27, 20, 12, 12, 6, 6, 2, 2, 18, 24, 44, 44, 56, 50, 54, 42
Offset: 1
Examples
First six rows: 2 4 3 2 6 6 8 2 2 8 9 14 9 6 2 2 10 12 20 16 16 6 6 2 2 12 15 26 23 26 17 12 6 6 2 2 For n=3, there are 9 triples (x,y,z) having x < z: 112: |x-y| + |y-z| = 1 113: |x-y| + |y-z| = 2 122: |x-y| + |y-z| = 1 123: |x-y| + |y-z| = 2 132: |x-y| + |y-z| = 3 133: |x-y| + |y-z| = 2 213: |x-y| + |y-z| = 3 223: |x-y| + |y-z| = 1 233: |x-y| + |y-z| = 1, so that row 1 of the array is (4,3,2), representing four 1s, three 2s, and two 3s.
Crossrefs
Programs
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Mathematica
t1[n_] := t1[n] = Tuples[Range[n], 3]; t[n_] := t[n] = Select[t1[n], #[[1]] < #[[3]] &]; a[n_, k_] := Select[t[n], Abs[#[[1]] - #[[2]]] + Abs[#[[2]] - #[[3]]] == k &]; u = Table[Length[a[n, k]], {n, 2, 15}, {k, 1, 2 n - 3}]; v = Flatten[u]; (* sequence *) Column[Table[Length[a[n, k]], {n, 2, 15}, {k, 1, 2 n - 3}]] (* array *)
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