cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A372211 a(n) = [x^n] f(x)^n, where f(x) = (1 - x^5)^5/((1 - x^2)^2 * (1 - x^3)^3).

Original entry on oeis.org

1, 0, 4, 9, 36, 125, 535, 1715, 7716, 26739, 111379, 419265, 1683351, 6518499, 26081381, 102089384, 408200740, 1612289384, 6441151477, 25602561864, 102352339411, 408402686750, 1635036583239, 6541552959219, 26227281703575, 105151396500125, 422159487904405, 1695369986497917
Offset: 0

Views

Author

Peter Bala, Apr 22 2024

Keywords

Comments

Let G(x) be a formal power series with integer coefficients. The sequence defined by g(n) = [x^n] G(x)^n satisfies the Gauss congruences: g(n*p^r) == g(n*p^(r-1)) (mod p^r) for all primes p and positive integers n and r.
We conjecture that in this case the stronger supercongruences a(n*p^r) == a(n*p^(r-1)) (mod p^(3*r)) hold for all primes p >= 5 and positive integers n and r. Some examples are given below. Cf. A351858.
More generally, if r is a positive integer and s an integer then the sequence defined by u(r,s; n) = [x^(r*n)] f(x)^(s*n) may satisfy the same supercongruences for primes p >= 7.
Even more generally, if a, b and m are a positive integers, with m = a + b, then the sequences whose n-th term equals [x^n] (1 - x^m)^m/((1 - x^a)^a * (1 - x^b)^b) or [x^n] (1 - x^m)^m/((1 + x^a)^a * (1 + x^b)^b) may both satisfy the above supercongruences for sufficiently large primes p depending on m.
The sequence of central binomial coefficients A000984 corresponds to the case m = 2 and a = b = 1.

Examples

			Supercongruences:
a(11) = 419265 = (3^2)*5*7*11^3 == 0 (mod 11^3).
a(23) = 6541552959219 = (3^2)*(23^3)*59738573 == 0 (mod 23^3).
a(2*7) - a(2) = 26081381 - 4 = (7^3)*76039 == 0 (mod 7^3).
		

References

  • R. P. Stanley, Enumerative Combinatorics Volume 2, Cambridge Univ. Press, 1999, Theorem 6.33, p. 197.

Crossrefs

Programs

  • Maple
    f(x) := (1 - x^5)^5/((1 - x^2)^2*(1 - x^3)^3):
    seq(coeftayl(f(x)^n, x = 0, n), n = 0..27);

Formula

The o.g.f. A(x) = 1 + 4*x^2 + 9*x^3 + 36*x^4 + ... is the diagonal of the bivariate rational function 1/(1 - t*f(x)) and hence is an algebraic function over the field of rational functions Q(x) by Stanley, Theorem 6.33, p. 197.