A374436 Triangle read by rows: T(n, k) = Product_{p in PF(n) union PF(k)} p, where PF(a) is the set of the prime factors of a.
1, 1, 1, 2, 2, 2, 3, 3, 6, 3, 2, 2, 2, 6, 2, 5, 5, 10, 15, 10, 5, 6, 6, 6, 6, 6, 30, 6, 7, 7, 14, 21, 14, 35, 42, 7, 2, 2, 2, 6, 2, 10, 6, 14, 2, 3, 3, 6, 3, 6, 15, 6, 21, 6, 3, 10, 10, 10, 30, 10, 10, 30, 70, 10, 30, 10, 11, 11, 22, 33, 22, 55, 66, 77, 22, 33, 110, 11
Offset: 0
Examples
[ 0] 1; [ 1] 1, 1; [ 2] 2, 2, 2; [ 3] 3, 3, 6, 3; [ 4] 2, 2, 2, 6, 2; [ 5] 5, 5, 10, 15, 10, 5; [ 6] 6, 6, 6, 6, 6, 30, 6; [ 7] 7, 7, 14, 21, 14, 35, 42, 7; [ 8] 2, 2, 2, 6, 2, 10, 6, 14, 2; [ 9] 3, 3, 6, 3, 6, 15, 6, 21, 6, 3; [10] 10, 10, 10, 30, 10, 10, 30, 70, 10, 30, 10; [11] 11, 11, 22, 33, 22, 55, 66, 77, 22, 33, 110, 11;
Crossrefs
Programs
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Maple
PF := n -> ifelse(n = 0, {}, NumberTheory:-PrimeFactors(n)): A374436 := (n, k) -> mul(PF(n) union PF(k)): seq(print(seq(A374436(n, k), k = 0..n)), n = 0..11);
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Mathematica
nn = 12; Do[Set[s[i], FactorInteger[i][[All, 1]]], {i, 0, nn}]; s[0] = {1}; Table[Apply[Times, Union[s[k], s[n]]], {n, 0, nn}, {k, 0, n}] // Flatten (* Michael De Vlieger, Jul 11 2024 *)
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Python
# Function A374436 defined in A374433. for n in range(12): print([A374436(n, k) for k in range(n + 1)])
Formula
T(0,0) = T(n,0) = 1; T(n,k) = rad(k*n) where rad = A007947. - Michael De Vlieger, Jul 11 2024