A376409 a(n) = A048675(A376408(n)); Partial sums of A376408.
0, 1, 3, 9, 99, 353529, 274407373885532679, 2443417474326613595267894539584266773823049253134356679026035220285823429
Offset: 0
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a(4) = 6, which is 110 in binary. So a(5) is the product of the primes corresponding to the 1's of 110, 3*5 = 15.
NestList[Times @@ Prime@ Flatten@ Position[#, 1] &@ Reverse@ IntegerDigits[#, 2] &, 1, 11] (* Michael De Vlieger, Aug 20 2017 *)
Starting with a(0) = 1, we take partial sums of previous terms, and apply A019565 to get the next term, and in the rightmost column, we "unbox" that term by applying A048675 to get A376407(n), which thus gives the partial sums of a(0)..a(n-1): a(0) = 1 -> 0 a(1) = A019565(1) = 2, -> 1 = 1 a(2) = A019565(1+2) = 6, -> 3 = 1+2 a(3) = A019565(1+2+6) = 14, -> 9 = 1+2+6 a(4) = A019565(1+2+6+14) = 330, -> 23 = 1+2+6+14 a(5) = A019565(1+2+6+14+330) = 10166, -> 353 = 1+2+6+14+330 a(6) = A019565(1+2+6+14+330+10166) = 12075690, -> 10519 = 1+2+6+14+330+10166 etc.
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