A376415 a(n) = A122245(4+n) XOR 16*A122245(n).

14488, 57880, 258096, 1033752, 3702824, 14821424, 66158736, 264831016, 948570032, 3798139024, 16949183552, 67829237680, 243080889928, 972279514176, 4341071097344, 17360471721544, 62225889019592, 248568875068928, 1111070190653712, 4438793067349704, 15908408008868528, 63634253845942544, 284082756299099488, 1136310075423425200

Offset: 1

Author

Antti Karttunen, Sep 22 2024

Keywords

• nonn
• base

Comments

This seems to preserve more of the "wavy texture" present in A122245 than what A376412 does vis-a-vis A122242. Compare the corresponding illustrations.

Links

• Antti Karttunen, Table of n, a(n) for n = 1..1650
• Antti Karttunen, Python program for computing this sequence and the associated images.
• Antti Karttunen, Terms a(1)-a(768) drawn as binary strings, in Wolframesque fashion.
• Antti Karttunen, The central parts of terms a(1) - a(20000) drawn in similar fashion. (the widening blank region in the middle corresponds with the "central crystallization" attractor present in A122245)
• Index entries for sequences related to binary expansion of n

Crossrefs

Cf. A122245 (A014486, A057548, A082358, A122237, A122244).

Cf. also A327973, A376405, A376412.

Programs

PARI

A376415(n) = bitxor(A122245(4+n), 16*A122245(n));

Python

# See the Links section