cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A380921 Least k such that A380783(k) = n.

Original entry on oeis.org

1, 2, 6, 15, 28, 40, 66, 91, 120, 144, 170, 204, 252, 299, 330, 374, 414, 475, 522, 570, 616, 667, 720, 798, 840, 910, 986, 1050, 1116, 1189, 1274, 1333, 1395, 1480, 1554, 1628, 1692, 1776, 1850, 1924, 2016, 2107, 2178, 2244, 2356, 2432, 2511, 2624, 2697, 2808
Offset: 1

Views

Author

Pontus von Brömssen, Feb 08 2025

Keywords

Crossrefs

Cf. A380783.

Formula

A380783(a(n)) = n.

A380751 Lexicographically earliest sequence of positive integers such that for any value k, no two sets of one or more indices at which k occurs have the same sum.

Original entry on oeis.org

1, 1, 2, 1, 2, 2, 2, 1, 3, 3, 3, 4, 3, 4, 4, 1, 2, 3, 4, 5, 5, 5, 4, 5, 6, 6, 5, 6, 7, 6, 7, 1, 5, 2, 6, 3, 7, 7, 8, 8, 6, 7, 8, 9, 8, 9, 4, 9, 9, 8, 10, 7, 10, 9, 10, 10, 8, 11, 10, 9, 11, 11, 11, 1, 10, 12, 12, 2, 11, 12, 13, 3, 12, 9, 12, 11, 10, 13, 13, 12
Offset: 1

Views

Author

Neal Gersh Tolunsky, Jan 31 2025

Keywords

Comments

The longest run in the sequence has length 3.
The powers of 2 (A000079) are the indices of 1s in this sequence.

Examples

			a(3) cannot be 1 since i = 1,2 would have the same sum as i = 3. So a(3) = 2.
a(12) cannot be 1 since i = 4,8 would have the same sum as i = 12. a(12) = 2 would give i = 12 the same sum as i = 5,7. a(12) = 3 would give i = 10,11 the same sum as i = 9,12. So a(12) = 4.
		

Crossrefs

Cf. A380783.

A380968 Lexicographically earliest sequence of positive integers such that for any value k, no two sets of one or more indices at which k occurs have the same mean.

Original entry on oeis.org

1, 1, 2, 1, 2, 2, 3, 1, 3, 3, 2, 4, 4, 5, 3, 1, 4, 5, 5, 6, 6, 7, 4, 6, 7, 2, 5, 8, 6, 3, 7, 1, 7, 5, 8, 8, 4, 9, 8, 9, 9, 10, 10, 6, 10, 9, 11, 11, 10, 11, 2, 8, 12, 11, 3, 7, 10, 12, 5, 12, 9, 11, 4, 13, 13, 14, 13, 12, 6, 14, 13, 14, 10, 15, 15, 16, 15, 11, 13
Offset: 1

Views

Author

Neal Gersh Tolunsky, Feb 09 2025

Keywords

Comments

A260873 gives the indices of 1s in the sequence.
The longest run in the sequence has length 2.
No three equal terms will appear at indices in arithmetic progression.
For any value k, the distances between pairs of k will be distinct.

Examples

			a(7) = 3: a(7) cannot be 1 because i = 4; i = 1,7; and i = 1,4,7 would all have the same mean index 4. a(7) cannot be 2 because i = 6; i = 5,6,7; and i = 5,7 would have the same mean index 6. So a(7) = 3.
a(19) cannot be 1, 2, or 3. a(19) = 4 does not work either because i = 13,19 would have the same mean (namely 16) as i = 12,17,19. So a(19) = 5.
		

Crossrefs

A381856 Lexicographically earliest sequence of positive integers such that for any value k, no two sets of two or more indices at which k occurs have the same standard deviation.

Original entry on oeis.org

1, 1, 2, 1, 2, 2, 3, 1, 3, 2, 4, 3, 3, 4, 4, 1, 5, 2, 5, 3, 4, 5, 4, 6, 1, 5, 6, 6, 2, 3, 7, 5, 6, 4, 6, 1, 7, 7, 8, 5, 7, 8, 8, 9, 6, 9, 2, 8, 3, 7, 4, 5, 9, 9, 8, 10, 9, 10, 10, 11, 7, 1, 8, 10, 11, 11, 6, 11, 9, 12, 10, 2, 12, 8, 11, 13, 12, 12, 3, 10, 13, 13
Offset: 1

Views

Author

Neal Gersh Tolunsky, Mar 08 2025

Keywords

Comments

A382381 gives the indices of 1s in this sequence.
If the definition is modified to compare all sets of indices whose terms are equal (not just those sets with the same value k), we get A337226.

Examples

			a(13) = 3: a(13) cannot be 1 as i = 4,13 would have the same standard deviation as i = 1,4,8,13 (namely 4.5). We cannot have a(13) = 2 because i = 3,6 would have the same standard deviation as i = 10,13 (namely 1.5). With a(13) = 3, we find that no two subsets of i = 7,9,12,13 have the same standard deviation, so a(13) = 3.
		

Crossrefs

Showing 1-4 of 4 results.