cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A381617 A sequence constructed by greedily sampling the zeta distribution for parameter value 2 to minimize discrepancy.

Original entry on oeis.org

1, 2, 1, 1, 3, 1, 4, 1, 1, 2, 1, 1, 5, 1, 2, 1, 1, 6, 1, 3, 1, 1, 2, 1, 7, 1, 1, 8, 1, 2, 1, 1, 4, 1, 3, 1, 2, 1, 1, 1, 9, 1, 2, 1, 1, 10, 1, 2, 1, 1, 3, 1, 5, 1, 1, 2, 1, 11, 1, 1, 4, 1, 2, 1, 1, 3, 1, 1, 2, 1, 12, 1, 1, 13, 1, 2, 1, 1, 3, 1, 6, 1, 2, 1, 1, 1, 4, 1, 2, 1, 1, 14
Offset: 1

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Author

Jwalin Bhatt, Mar 10 2025

Keywords

Comments

The geometric mean approaches exp(-zeta'(2)/zeta(2)) = A381456 in the limit.
The zeta distribution PDF is p(i) = 1/(zeta(2)*i^2).

Examples

			Let p(k) denote the probability of k and c(k) denote the number of occurrences of k among the first n-1 terms; then the expected number of occurrences of k among n random terms is given by n*p(k).
We subtract the actual occurrences c(k) from the expected occurrences and pick the one with the highest value.
| n | n*p(1) - c(1) | n*p(2) - c(2) | n*p(3) - c(3) | choice |
|---|---------------|---------------|---------------|--------|
| 1 |     0.607     |       -       |       -       |   1    |
| 2 |     0.215     |     0.303     |       -       |   2    |
| 3 |     0.823     |    -0.544     |     0.202     |   1    |
| 4 |     0.431     |    -0.392     |     0.270     |   1    |
| 5 |     0.039     |    -0.240     |     0.337     |   3    |
		

Crossrefs

Programs

  • Mathematica
    probCountDiff[j_, k_, count_] := k/(Zeta[2] j^2) - Lookup[count, j, 0]
    samplePDF[n_] := Module[{coeffs, unreachedVal, counts, k, probCountDiffs, mostProbable},
      coeffs = ConstantArray[0, n]; unreachedVal = 1; counts = <||>;
      Do[probCountDiffs = Table[probCountDiff[i, k, counts], {i, 1, unreachedVal}];
        mostProbable = First@FirstPosition[probCountDiffs, Max[probCountDiffs]];
        If[mostProbable == unreachedVal, unreachedVal++]; coeffs[[k]] = mostProbable;
        counts[mostProbable] = Lookup[counts, mostProbable, 0] + 1;, {k, 1, n}]; coeffs]
    A381617 = samplePDF[120]