A383169 Triangle T(n,k) read by rows: For closed chains of j identical regular polygons with connecting inner vertices lying n vertices apart, the n-th row lists the possible j in descending order; n>=0, 1<=k<=d(8+4n).
10, 6, 4, 3, 14, 8, 6, 5, 4, 3, 18, 10, 6, 4, 3, 22, 12, 7, 6, 4, 3, 26, 14, 10, 8, 6, 5, 4, 3, 30, 16, 9, 6, 4, 3, 34, 18, 10, 6, 4, 3, 38, 20, 14, 11, 8, 6, 5, 4, 3, 42, 22, 12, 10, 7, 6, 4, 3, 46, 24, 13, 6, 4, 3, 50, 26, 18, 14, 10, 8, 6, 5, 4, 3
Offset: 1
Examples
Triangle begins: 10, 6, 4, 3; 14, 8, 6, 5, 4, 3; 18, 10, 6, 4, 3; 22, 12, 7, 6, 4, 3; 26, 14, 10, 8, 6, 5, 4, 3; 30, 16, 9, 6, 4, 3; 34, 18, 10, 6, 4, 3; 38, 20, 14, 11, 8, 6, 5, 4, 3; 42, 22, 12, 10, 7, 6, 4, 3; 46, 24, 13, 6, 4, 3; 50, 26, 18, 14, 10, 8, 6, 5, 4, 3; ... The third row T(2,.) asserts that closed chains of identical regular polygons with connecting inner vertices lying 2 vertices apart can only be assembled with 18, 10, 6, 4 or 3 polygons.
Links
- Manfred Boergens, Closed chains of polygons.
Programs
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Mathematica
Table[2 + Sort[Divisors[8 + 4 n], Greater], {n, 0, 10}]//Flatten
Formula
T(n,k) = 2 + (k-th divisor of 8+4n in descending order).
T(n,k) = 2 + (8+4n)/(A383168(n,k)-4-2n).
A383168(n,k) = 4 + 2n + (8+4n)/(T(n,k)-2).
T(n,1) = 10 + 4n.
T(n,2) = 6 + 2n.
T(n,2) = A383168(n,2).
T(n,3) = (2/3)*(7+2n) if n=1 mod 3, else = 4+n.
T(n,d(8+4n)) = 3 (last row elements).
T(n,d(8+4n)-1) = 4 (second to last row elements).
T(n,d(8+4n)-2) = 5 if n=1 mod 3, else = 6 (third last row elements).
Comments