A383168 Triangle T(n,k) read by rows: For closed chains of identical regular m-gons with connecting inner vertices lying n vertices apart, the n-th row lists the possible m in ascending order; n>=0, 1<=k<=d(8+4n).
5, 6, 8, 12, 7, 8, 9, 10, 12, 18, 9, 10, 12, 16, 24, 11, 12, 14, 15, 20, 30, 13, 14, 15, 16, 18, 20, 24, 36, 15, 16, 18, 21, 28, 42, 17, 18, 20, 24, 32, 48, 19, 20, 21, 22, 24, 27, 30, 36, 54, 21, 22, 24, 25, 28, 30, 40, 60, 23, 24, 26, 33, 44, 66
Offset: 1
Examples
Triangle begins: 5, 6, 8, 12; 7, 8, 9, 10, 12, 18; 9, 10, 12, 16, 24; 11, 12, 14, 15, 20, 30; 13, 14, 15, 16, 18, 20, 24, 36; 15, 16, 18, 21, 28, 42; 17, 18, 20, 24, 32, 48; 19, 20, 21, 22, 24, 27, 30, 36, 54; 21, 22, 24, 25, 28, 30, 40, 60; 23, 24, 26, 33, 44, 66; 25, 26, 27, 28, 30, 32, 36, 40, 48, 72; ... The third row T(2,.) asserts that regular 9-gons, 10-gons, 12-gons, 16-gons and 24-gons are the only regular polygons which can be assembled to a closed chain with connecting inner vertices lying 2 vertices apart.
Links
- Manfred Boergens, Closed chains of polygons.
Programs
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Mathematica
Table[4 + 2*n + Divisors[8 + 4 n], {n, 0, 10}]//Flatten
Formula
T(n,k) = 4+2n + (k-th divisor of 8+4n in ascending order).
T(n,k) = 4+2n + A027750(8+4n,k).
T(n,k) = 4+2n + (8+4n)/(A383169(n,k)-2).
A383169(n,k) = 2 + (8+4n)/(T(n,k)-4-2n).
T(n,1) = 5+2n.
T(n,2) = 6+2n.
T(n,2) = A383169(n,2).
T(n,3) = 7+2n if n=1 mod 3, else = 8+2n.
T(n,3) = A047244(5+n).
T(n,d(8+4n)) = 12+6n (last row elements).
T(n,d(8+4n)-1) = 8+4n (second to last row elements).
T(n,d(8+4n)-2) = (10/3)*(2+n) if n=1 mod 3, else = 3*(2+n) (third last row elements).
Comments