cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A385186 Numbers y such that there exists an integer 0 < x < y such that sigma(x)^x * sigma(y)^y = (x+y)^(x+y).

Original entry on oeis.org

284, 1210, 2924, 5564, 6368, 10856, 14595, 18416, 76084, 66992, 71145, 87633, 88730, 124155, 139815, 123152, 153176, 168730, 176336, 180848, 203432, 202444, 365084, 389924, 430402, 399592, 455344, 486178, 514736, 525915, 669688, 686072
Offset: 1

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Author

S. I. Dimitrov, Jun 20 2025

Keywords

Comments

The numbers x and y form a WGM-amicable pair (WGM = Weighted Geometric Mean). See Dimitrov link. An amicable pair forms a WGM-amicable pair, so the larger member of an amicable pair A002046 is a term of this sequence. A check for x < y < 2*10^6 shows that all solutions (x,y) to the Diophantine equation sigma(x)^x * sigma(y)^y = (x+y)^(x+y) are amicable pairs. Although we cannot set an example, we cannot rule out the existence of WGM-amicable pairs that are not amicable pairs.
It is important to note that the brute-force search should be performed on the logarithmic form of the equation: x*log(sigma(x)) + y*log(sigma(y)) = (x+y) * log(x+y).

Examples

			(220, 284) is such a pair because sigma(220)^220*sigma(284)^284 = (220+284)^(220+284).
		

Crossrefs

A386010 Numbers z such that there exist two integers 0

Original entry on oeis.org

120, 672, 1188, 1740, 2556, 11172, 11556, 11628, 27312, 32136, 41412, 41952, 42168
Offset: 1

Views

Author

S. I. Dimitrov, Jul 14 2025

Keywords

Comments

The numbers x, y and z form a GM-amicable triple (GM = Geometric Mean). See Dimitrov link. An amicable triple forms a GM-amicable triple, so the larger member of an amicable triple A125492 is a term of this sequence.

Examples

			(1080, 1092, 1188) is such a triple because sigma(1080)*sigma(1092)*sigma(1188) = (1080 + 1092 + 1188)^3.
		

Crossrefs

Showing 1-2 of 2 results.