A384661 Solution of the complementary equation b(n)=a(a(n))+a(n)+2 with a(1)=1; this is the sequence a(n).
1, 2, 3, 5, 7, 9, 10, 11, 12, 13, 15, 16, 17, 18, 20, 21, 22, 24, 26, 27, 29, 31, 33, 34, 35, 36, 38, 40, 42, 43, 45, 46, 47, 48, 50, 51, 53, 54, 56, 57, 58, 59, 61, 62, 63, 65, 66, 68, 69, 70, 71, 72, 74, 75, 76, 77, 79, 80, 81, 83, 85, 86, 88, 90, 91, 92
Offset: 1
Keywords
Examples
b(1) = a(a(1))+a(1)+2 = 1+1+2 = 4; b(2) = a(a(2))+a(2)+2 = 2+2+2 = 6; b(3) = a(a(3))+a(3)+2 = 3+3+2 = 8; b(4) = a(a(4))+a(4)+2 = 5+7+2 = 14.
Links
- Clark Kimberling, Complementary equations, J. Int. Seq. Article 07.1.4 (2007), 1-13.
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