cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A144608 Christoffel word of slope 10/11.

Original entry on oeis.org

0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1
Offset: 0

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Author

N. J. A. Sloane, Jan 13 2009

Keywords

Comments

The path is on the slope after 0, 21, 42, 63, 84,... steps (A008603), which gives the simple C-finite recurrence. - R. J. Mathar, May 28 2025

Crossrefs

See A144595 for further details.

Formula

a(n) = a(n-21). - R. J. Mathar, May 28 2025
G.f.: -x^2*(1+x^2)*(x^8-x^6+x^4-x^2+1)*(x^4-x^3+x^2-x+1)*(1+x+x^2+x^3+x^4) / ( (x-1)*(1+x^6+x^5+x^4+x^3+x^2+x)*(1+x+x^2)*(1-x+x^3-x^4+x^6-x^8+x^9-x^11+x^12) ). - R. J. Mathar, May 28 2025

A242570 a(n) = 252 * n.

Original entry on oeis.org

0, 252, 504, 756, 1008, 1260, 1512, 1764, 2016, 2268, 2520, 2772, 3024, 3276, 3528, 3780, 4032, 4284, 4536, 4788, 5040, 5292, 5544, 5796, 6048, 6300, 6552, 6804, 7056, 7308, 7560, 7812, 8064, 8316, 8568, 8820, 9072, 9324, 9576, 9828, 10080, 10332, 10584, 10836, 11088, 11340
Offset: 0

Views

Author

Derek Orr, May 17 2014

Keywords

Comments

As lcm(1,2,3,...,9) = 2520, 10*a(n) + k is divisible by each k from 1 through 9.

Crossrefs

Programs

  • Mathematica
    252*Range[0, 49] (* Alonso del Arte, May 17 2014 *)
    LinearRecurrence[{2,-1},{0,252},50] (* Harvey P. Dale, Mar 25 2025 *)
  • PARI
    for(n=0,50,print(252*n))

Formula

From Elmo R. Oliveira, Apr 16 2024: (Start)
G.f.: 252*x/(x-1)^2.
E.g.f.: 252*x*exp(x).
a(n) = 2*a(n-1) - a(n-2) for n >= 2.
a(n) = 7*A044102(n) = 9*A135628(n) = 12*A008603(n) = 14*A008600(n) = 18*A008596(n) = 21*A008594(n) = 28*A008591(n) = 36*A008589(n) = 252*A001477(n). (End)
Previous Showing 11-12 of 12 results.